Python为图像添加额外区域 [英] Python adding extra area to image

问题描述

所以我有一张图片大小的表格。有像7（66x66,400x400等）
我有一个图像的例子，原始的，总是有600x532的大小。
这个原版可以是电视，PC，...一些产品。
现在我必须调整此图像的大小。那没问题。但如果我按比例做，我会得到类似的东西：66x55。如果我不做比例，图像看起来不太好。

So I have a table with image sizes. There are like 7 (66x66, 400x400, etc.) And I have one example of image, the original, that always has a size of 600x532. On this original can be a TV, a PC, ... some products. Now I have to resize this image. It is no problem. But if I do with proportion I get something like: 66x55. If i dont do with proportion the image doesnt look good.

因此原始背景总是白色。有没有办法扩展图像的区域，并用白色填充其余部分？
所以像这样：600x532 - > 600x600 - > 66x66等等。

So the background of the original is always white. Is there a way to extend the area of the image and filling the rest with white? So like this: 600x532 -> 600x600 -> 66x66 etc etc.

它应该像反作物。

编辑：我发现如果我使用PIL中的crop（）而不是使用高于实际图像大小的值最小化它会创建我的额外区域。但它会变成黑色。
我知道如何填补这个区域的白色吗？

I found out that if I use crop() from PIL and instead of "minimizing" using a value above the actual image-size it creates my extra area. but it is going to be black. Any idea how I could fill this area white?

EDIT2：我想这与ImageDraw有关。

I guess it has something to do with ImageDraw.

EDIT3：在发现ImageDraw是解决方案之后，我的问题就解决了。请关闭此。

After finding out that ImageDraw was the solution, my problem was solved. Please close this.

这里我的解决方案：

import Image, ImageDraw
img1 = Image.open("img.jpg")
img2 = img1.crop((0,0,600,600))
draw = ImageDraw.Draw(img2)
draw.rectangle( (0,532,600,600), fill='white' )
del draw
img2.save("img2.jpg","JPEG", quality=75)

接下来我要做的就是让额外的作物上下。所以图片保持在中间位置。

The next thing I will do is to make the extra crop above and under. So the picture stays in the middle.

EDIT4：最终解决方案

final solution

img1 = Image.open("img1.jpg")
img2 = img1.crop( (0,-34,600,566) )  
draw = ImageDraw.Draw(img2)
draw.rectangle( (0,0,600,34), fill="white" )
draw.rectangle( (0,566,600,600), fill="white" )
del draw
img2.save("img2.jpg", "JPEG", quality=75)

推荐答案

假设我们使用PIL来处理图像

Supposing we use PIL to process the image

from PIL import Image

def white_bg_square(img):
    "return a white-background-color image having the img in exact center"
    size = (max(img.size),)*2
    layer = Image.new('RGB', size, (255,255,255))
    layer.paste(img, tuple(map(lambda x:(x[0]-x[1])/2, zip(size, img.size))))
    return layer

您可以调整PIL图像对象的大小，例如img

You could resize a PIL Image object, img for example

img.resize((width, height), resample=Image.ANTIALIAS)

因此在python shell中，它看起来像

Thus in the python shell, it looks like

>>> from PIL import Image
>>> img = Image.open('path/to/image')
>>> square_one = white_bg_square(img)
>>> square_one.resize((100, 100), Image.ANTIALIAS)
>>> square_one.save('path/to/result')

在PIL文档和sorl中有很好的例子-thumbnail 3.2.5

There are nice examples inside PIL document and sorl-thumbnail 3.2.5

• http://effbot.org/imagingbook/image.htm


• http://pypi.python.org/pypi/sorl-thumbnail/3.2.5

• http://effbot.org/imagingbook/image.htm
• http://pypi.python.org/pypi/sorl-thumbnail/3.2.5

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