onClick（），onMouseOver（）和onMouseOut（）与图像 [英] onClick(), onMouseOver() and onMouseOut() with image

问题描述

到目前为止，我已经有了这个工作，因此它有一个基本图像，点击图像，并将图像更改为活动图像，但我不希望它在鼠标移出时恢复原始图像如果图像已被点击 - 我希望它保持在点击图像上，直到点击另一个图像。

So far I've got this working so that it has a "basic" image, click image, and change image to "active image, but I don't want it to revert back to the original image when you mouse out if the image has been clicked--I want it to stay on the click image until another image is clicked.

这是我的HTML

      <div id="booking_i">
       <img id="img" src="/design/zebra/images/booking/1stolik.png">
       <img id="img2" src="/design/zebra/images/booking/2stolik.png">
      </div>

在js中就像

onmouseover="image.src='/design/zebra/images/booking/1stolik_aktiv.png'";
onmouseout="image.src='/design/zebra/images/booking/1stolik.png'";
onClick="image.src='/design/zebra/images/booking/1stolik_clicked.png'";

推荐答案

HTML

<div id="booking_i">
    <img id="inage1" src="/design/zebra/images/booking/booking.png" />
    <img id="img" src="/design/zebra/images/booking/1stolik.png" />
    <img id="img2" src="/design/zebra/images/booking/2stolik.png" />
</div>

CSS

#image1 {
    position: absolute;
    left: 103px;
    top: 300px;
}

jQuery

$(document).ready(function () {
    $('#img').onMouseOver.attr('src','/design/zebra/images/booking/1stolik_active.png');
    $('#img').click(function () {
        this.attr('src', '/design/zebra/images/booking/1stolik_clicked.png');
        $('#img2').attr('src','/design/zebra/images/booking/2stolik.png');
    });
    $('#img2').onMouseOver.attr('src','/design/zebra/images/booking/2stolik_active.png');
    $('#img2').click(function () {
        this.attr('src', '/design/zebra/images/booking/2stolik_clicked.png');
        $('#img').attr('src','/design/zebra/images/booking/1stolik.png');
    });
});

这篇关于onClick（），onMouseOver（）和onMouseOut（）与图像的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！