如何在C＃中混合来自两种不同方法的输出图像？ [英] How can I mix output images from two different methods in C#?

问题描述

我遇到如下问题，

我有一个基于C＃的应用程序，它有两行图像生成：

I have an application based on C# which has two lines of image production:

Line-1基于某些数学计算每秒生成一系列帧。每个帧（图像）由黑色和白色像素组成，它们形成一个模式。

Line-1 generates a series of frames per second based on some mathematical calculation. Each frame (image) is consist of black and white pixels which they form a pattern.

Line-2生成另一系列基于随机噪声发生器的帧。所以它们只是不同的帧，只包含噪音！
现在，我的问题是我需要将这两行中的帧随机混合在一起。通过这意味着，例如，我需要从第1行选择5帧，从第2行选择3帧，依此类推，将它们随机混合在一起。这种混合程序将随机改变。

Line-2 is generating another series of frames which are made based on random noise generator. So they are just different frames which contain only noise! Now, my question is I need to mix this frames from these two lines together randomly. By meaning that, for example I need to select 5 frames from line-1 and 3 frames from line-2 and so on mixing them together randomly. This mixing procedure will change randomly.

我自己的解决方案是，如果我将第1行生产中的图像存储在单独的列表中，而将第2行生成存储在另一个列表中，那么我可以有一个标志从这两个列表中随机选择。但是，由于这些图像实时生成，我不知道该解决方案是否有效。有没有人对我的问题有任何替代解决方案？;）

My own solution is if I store images from line-1 production in a separate list, and line-2 production in another list so I can have a flag to select from these two lists randomly. But as a fact that this images are generating real time I don’t know if that solution works or not. Does anyone have any alternative solution for my question?;)

推荐答案

我会使用队列（队列（ T）或 ConcurrentQueue（T））来存储图像。假设您使用一个线程来填充每个队列，并使用一个线程从两个队列中消耗。

I would use queues (Queue(T) or ConcurrentQueue(T)) to store the images. Assuming you use a thread to fill each queue and one to consume from both queues.

示例：

  private ConcurrentQueue<Bitmap> line1 = new ConcurrentQueue<Bitmap>();
  private ConcurrentQueue<Bitmap> line2 = new ConcurrentQueue<Bitmap>();
  private Random randomGenerator = new Random();

  //thread 1
  private void FillLine1()
  {
     //your line 1 image producation code
     Bitmap yourCalculatedBitmap = new Bitmap(100,100);
     line1.Enqueue(yourCalculatedBitmap);
  }

  //thread 2
  private void FillLine2()
  {
     //your line 2 image production code
     Bitmap yourCalculatedBitmap = new Bitmap(100,100);
     line1.Enqueue(yourCalculatedBitmap);
  }

  //thread 3
  private Bitmap RandomImageSelection()
  {
     Bitmap image;

     if (randomGenerator.Next(2) == 0 && line1.TryDequeue(out image))
     {
        return image;
     }

     if (line2.TryDequeue(out image))
     {
        return image;
     }

     return null;
  }

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