module.exports in typescript [英] module.exports in typescript

问题描述

有人知道怎么做module.exports吗？

我尝试了一些不同的方式结束

< pre class =lang-default prettyprint-override> export class Greeter {}


将编译为

  exports.Greeter = Greeter; 
  

但我真正想要的是：

  exports = Greeter; 
  

这样我可以像这样使用它：

  import Greeter = module（Greeter）; 
 var greeter = new Greeter（）; 
  

而不是

  import Greeter = module（Greeter）; 
 var greeter = new Greeter.Greeter（）; 
  

这是否可以使用Typescript？

解决方案

您可以在TypeScript中导出单个类，如下所示：

  class Person {
 
 private firstName：string; 
 private lastName：string; 
 
构造函数（firstName：string，lastName：string）{
 this.firstName = firstName; 
 this.lastName = lastName; 
} 
 
 public getFullName（）{
 return` $ {this.firstName} $ {this.lastName}`; 
} 
} 
 
 export = Person; 
  

以下是它的使用方法：

  var Person = require（'./ dist / commonjs / Person.js'）; 
 
 var homer = new Person（'Homer'，'Simpson'）; 
 var name = homer.getFullName（）; 
 
 console.log（name）; //荷马辛普森
  

要完成，这是我的 tsconfig.json （我使用的是TypeScript v2.0.3）：

  {
compilerOptions：{
module ：commonjs，
moduleResolution：node，
outDir：dist / commonjs，
rootDir：src / ts，
 target：es5
}，
exclude：[
dist，
node_modules
] 
} 
  

does somebody know how to do a module.exports?

I tried some different ways ending up with

export class Greeter {}

which will compile to

exports.Greeter = Greeter;

But what I really want is this:

exports = Greeter;

So that I can use it like this:

import Greeter = module("Greeter");
var greeter = new Greeter();

and not

import Greeter = module("Greeter");
var greeter = new Greeter.Greeter();

Is this possible with Typescript?

解决方案

You can export a single class in TypeScript like this:

class Person {

  private firstName: string;
  private lastName: string;

  constructor(firstName: string, lastName: string) {
    this.firstName = firstName;
    this.lastName = lastName;
  }

  public getFullName() {
    return `${this.firstName} ${this.lastName}`;
  }
}

export = Person;

And here is how it's going to be used:

var Person = require('./dist/commonjs/Person.js');

var homer = new Person('Homer', 'Simpson');
var name = homer.getFullName();

console.log(name); // Homer Simpson

To be complete, here is my tsconfig.json (I am using TypeScript v2.0.3):

{
  "compilerOptions": {
    "module": "commonjs",
    "moduleResolution": "node",
    "outDir": "dist/commonjs",
    "rootDir": "src/ts",
    "target": "es5"
  },
  "exclude": [
    "dist",
    "node_modules"
  ]
}

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