在PHP中获取包含在字符串中的结果？ [英] Get the Results of an Include in a String in PHP?

问题描述

让我们说文件test.php看起来像这样：

Let's say file test.php looks like this:

<?php
echo 'Hello world.';
?>

我想做这样的事情：

$test = include('test.php');

echo $test;

// Hello world.

有人能指出我走正确的道路吗？

Can anyone point me down the right path?

编辑：

我最初的目标是将PHP代码与HTML混合在一起并将其处理出来。以下是我最终要做的事情：

My original goal was to pull PHP code intermingled with HTML out of a database and process it. Here's what I ended up doing:

// Go through all of the code, execute it, and incorporate the results into the content
while(preg_match('/<\?php(.*?)\?>/ims', $content->content, $phpCodeMatches) != 0) {
    // Start an output buffer and capture the results of the PHP code
    ob_start();
    eval($phpCodeMatches[1]);
    $output = ob_get_clean();

    // Incorporate the results into the content
    $content->content = str_replace($phpCodeMatches[0], $output, $content->content);
}

推荐答案

使用输出缓冲是最好的选择。

ob_start();
include 'test.php';
$output = ob_get_clean();

PS：请记住，如果需要，您也可以将输出缓冲区嵌套到心中。 。

PS: Remember that you can nest output buffers to your hearts content as well if needed.

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