`which（）`用于矩阵索引的函数 [英] `which()` function for matrix indices

问题描述

说我有一些矩阵，例如：

Say I have some matrix, for example:

> m = matrix(rep(c(0, 0, 1), 4), nrow = 4)
> m
     [,1] [,2] [,3]
[1,]    0    0    1
[2,]    0    1    0
[3,]    1    0    0
[4,]    0    0    1

如果我运行哪个，我得到正常指数列表：

If I run which, I get list of normal indices:

> which(m == 1)
[1]  3  6  9 12

我想要得到类似矩阵索引的东西 - 每个索引包含行号和列号：

I want to get something like matrix indices - each index containing the row and column number:

     [,1] [,2]
[1,]    3    1
[2,]    2    2
[3,]    1    3
[4,]    4    3

是否有任何简单的函数可以执行此操作？此外，它应该以某种方式包含行和列名称：

Is there any simple function to do this? Moreover, it should somehow contain the row and column names:

> rownames(m) = letters[1:4]
> colnames(m) = letters[5:7]
> m
  e f g
a 0 0 1
b 0 1 0
c 1 0 0
d 0 0 1

但我现在不怎么样，或许像

but I don't now how, maybe like

     [,1] [,2] [,3] [,4]
[1,]    3    1    c    e
[2,]    2    2    b    f
[3,]    1    3    a    g
[4,]    4    3    d    g

或者，可能返回2个向量（用于行和列），如

or, maybe return 2 vectors (for rows and columns), like

c b a d
3 2 1 4

e f g g
1 2 3 3

推荐答案

对于第一个问题，您还需要传递 arr.ind = T 到哪个：

For your first question you need to also pass arr.ind=T to which:

> which(m == 1, arr.ind=T)
     row col
[1,]   3   1
[2,]   2   2
[3,]   1   3
[4,]   4   3

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