循环遍历字符串以查找多个索引 [英] Looping Through String To Find Multiple Indexes

问题描述

我试图找出循环字符串并查找某个字母的所有索引的最有效方法。

I am trying to figure out the most efficient way of looping through a string and finding all indexes of a certain letter.

我使用过 $ word_or_phrase.indexOf（$ letter）; 查找单个索引的字母，但该字母多次在 $ word_or_phrase 中。最有效的方法是构建所有索引的数组，直到 .indexOf 返回-1？或者您如何建议我找到所有索引？

I have used $word_or_phrase.indexOf( $letter ); to find a single index of a letter, but the letter is in $word_or_phrase multiple times. Would the most efficient way to do this be to build an array of all the indexes until .indexOf returns -1? Or how would you suggest me finding all the the indexes?

我已经花时间找到了这个：
Javascript str.search（）多个实例

I have already taken time and found this: Javascript str.search() multiple instances

这样可行，但对我来说，处理2个以上的效果似乎并不高效索引。如果我有10个怎么办？

This works, but to me doesn't seem efficient when dealing with more than 2 indexes. What if I had 10?

提前感谢您的建议！

推荐答案

可能是一个解决方案：

http：// jsfiddle .net / HkbpY /

var str = 'some kind of text with letter e in it',
    letter = 'e',
    indexes = [];

$.each(str.split(''),function(i,v){
    if(v === letter) indexes.push(i);
});

console.log(indexes);

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