如何从孙子类中调用超级方法？ [英] How to call super method from grandchild class?

问题描述

我正在处理一些具有3级继承级别的代码。从最低级别的派生类，调用方法2的语法是什么？超级电话？ 中间类没有实现我需要调用的方法。

I am working with some code that has 3 levels of class inheritance. From the lowest level derived class, what is the syntax for calling a method 2 levels up the hierarchy, e.g. a super.super call? The "middle" class does not implement the method I need to call.

推荐答案

嗯，这是一种方法：

class Grandparent(object):
    def my_method(self):
        print "Grandparent"

class Parent(Grandparent):
    def my_method(self):
        print "Parent"

class Child(Parent):
    def my_method(self):
        print "Hello Grandparent"
        Grandparent.my_method(self)

也许不是你想要的，但它是最好的python，除非我弄错了。你问的是什么声音反pythonic，你必须解释为什么你这样做让我们给你愉快的python做事方式。

Maybe not what you want, but it's the best python has unless I'm mistaken. What you're asking sounds anti-pythonic and you'd have to explain why you're doing it for us to give you the happy python way of doing things.

另一个例子，也许你想要的（来自你的评论）：

Another example, maybe what you want (from your comments):

class Grandparent(object):
    def my_method(self):
        print "Grandparent"

class Parent(Grandparent):
    def some_other_method(self):
        print "Parent"

class Child(Parent):
    def my_method(self):
        print "Hello Grandparent"
        super(Child, self).my_method()

如您所见， Parent 未实现 my_method 但是 Child 仍然可以使用super来获取 Parent 看到的方法，即祖父母的 my_method 。

As you can see, Parent doesn't implement my_method but Child can still use super to get at the method that Parent "sees", i.e. Grandparent's my_method.

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