在Rails中跳过before_filter [英] Skip before_filter in Rails

问题描述

为了清楚起见，简化了名称和对象。基本概念保持不变。

Names and objects have been simplified for clarity's sake. The basic concept remains the same.

我有三个控制器： dog ， cat 和马。
这些控制器都继承自控制器 animal 。
在控制器 animal 中，我有一个before过滤器，用于对用户进行身份验证：

I have three controllers: dog, cat, and horse. These controllers all inherit from the controller animal. In the controller animal, I have a before filter that authenticates a user as such:

before_filter :authenticate

def authenticate
  authenticate_or_request_with_http_basic do |name, password|
    name == "foo" && password == "bar"
  end
end

在 show dog 的操作，我需要对所有用户具有开放访问权限（跳过身份验证）。

In the show action of dog, I need to have open access to all users (skip the authentication).

如果我要为 dog 单独编写身份验证，我可以这样做：

If I were to write the authentication separately for dog, I could do something like this:

before_filter :authenticate, :except => :show

但是因为 dog 继承自 animal ，我无法访问特定于控制器的操作。添加：except => ：动物控制器中的show 不仅会跳过 show 操作的身份验证 dog ，还包括 cat 和 horse 。不希望出现这种情况。

But since dog inherits from animal, I do not have access to the controller-specific actions. Adding :except => :show in the animal controller will not only skip authentication for the show action of dog, but also that of cat and horse. This behaviour is not desired.

如何仅针对<$ c $的 show 操作跳过身份验证c> dog ，但仍然继承自 animal ？

How can I skip the authentication only for the show action of dog while still inheriting from animal?

推荐答案

class Dog < Animal
  skip_before_filter :authenticate, :only => :show
end

参见 ActionController :: Filters :: ClassMethods ，了解有关过滤器和继承的更多信息。

See ActionController::Filters::ClassMethods for more info on filters and inheritance.

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