python 2.7 __init __（）需要2个参数（给定3个） [英] python 2.7 __init__() takes exactly 2 arguments (3 given)

问题描述

我有这些课程。
人是父类，学生是子类：

I've got These classes. person is the parent class and student is the child class:

#Person class
class person(object):
    def __init__(self, name):
        self.name = name
    def pr(self):
        print "I'm " + self.name 

#Student class
from personClass import person
class student(person):
    def __init__(self, avr, name):
        self.avr = avr
        super(student, self).__init__(self, name)
    def pr(self):
        super(student, self).pr(self)
        print "My avrage is " + str(self.avr) + "\n"

我在网上收到此错误17当我尝试创建我的类的实例时 init （）只需要2个参数（3个给定）和
个人。 init （self，name）有效精细。
我的代码有什么问题，我如何在python 2.7中使用super？

I get this error on line 17 when I try to make an instance of my class init() takes exactly 2 arguments (3 given) and person.init(self, name) works fine. What is wrong with my code and how do I use super in python 2.7?

推荐答案

如果你使用超级，您不会将 self 传递给目标方法。隐式传递。

If you are using super, you don't pass self to the target method. It is passed implicitly.

super(student, self).__init__(name)

总共有2个参数（self，name）。当您通过 self 时，这总共为3（自我，自我，姓名）。

That's 2 arguments total (self, name). When you passed self, that was 3 total (self, self, name).

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