在它前面具有零的整数是什么意思,我该如何打印它? [英] What does an integer that has zero in front of it mean and how can I print it?
问题描述
class test {
public static void main(String args []){
int a = 011;
System.out.println(a);
}
}
为什么我得到 9
作为输出而不是 011
?
我如何获得 011
作为输出?
解决方案:
如果你希望你的整数保持值11,那么不要花哨,只需分配11.毕竟,符号不会改变任何值。我的意思是,从数学的角度来看11 = 011 = 11,0。
int a = 11;
格式化仅在您打印时(或转换 int时)很重要
到字符串
)。
String with3digits = String.format(%03d,a);
System.out.println(with3digits);
使用格式化程序%03d
添加前导零。
或者,你可以在1行,使用 printf
方法。
System.out.printf (%03d,a);
class test{
public static void main(String args[]){
int a = 011;
System.out.println(a);
}
}
Why I am getting 9
as output instead of 011
?
How can I get 011
as output?
The JLS 3.10.1 describes 4 ways to define integers.
An integer literal may be expressed in decimal (base 10), hexadecimal (base 16), octal (base 8), or binary (base 2).
An octal numeral consists of a digit 0 followed by one or more of the digits 0 through 7 ...
A decimal numeral is either the single digit 0, representing the integer zero, or consists of an digit from 1 to 9 optionally followed by one or more digits from 0 to 9 ...
In summary if your integer literal (i.e. 011
) starts with a 0, then java will assume it's an octal notation.
Solutions:
If you want your integer to hold the value 11, then don't be fancy, just assign 11. After all, the notation doesn't change anything to the value. I mean, from a mathematical point of view 11 = 011 = 11,0.
int a = 11;
The formatting only matters when you print it (or when you convert your int
to a String
).
String with3digits = String.format("%03d", a);
System.out.println(with3digits);
The formatter "%03d"
is used to add leading zeroes.
Alternatively, you could do it in 1 line, using the printf
method.
System.out.printf("%03d", a);
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