在String值后面打印一个int值 [英] printing an int value right after a String value

问题描述

我有以下示例代码：

int pay = 80;
int bonus = 65;
System.out.println(pay + bonus + " " + bonus + pay);

有人可以向我解释为什么我会得到以下输出：

could someone please explain to me why I get the following output:

145 6580

推荐答案

您的代码是从左到右解释表达式。

Your code is interpreting the expression from left to right.

1. pay + bonus 被解释为数学函数，因此它将值添加到145. + 这里是一个加号运算符。


2. 当您连接时，Java会将表达式转换为String。这里的 + 是一个连接运算符。


3. 执行 + pay 转换支付到一个字符串并连接它，因为表达式是一个字符串。


4. 还要做 + bonus 将 bonus 转换为String并连接它，也因为前一个表达式。

1. pay + bonus is interpreted as a mathematical function, so it adds the values to make 145. The + here is a plus operator.
2. The moment you concatenate the " ", Java converts the expression into a String. The + here is a concatenate operator.
3. Performing + pay converts pay to a String and concatenates it, because the expression is a String.
4. Also doing + bonus converts bonus to a String and concatenates it, also because of the previous expression.

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