如何在C中通过udp socket发送整数数组？ [英] How to send integer array over udp socket in C?

问题描述

我必须通过udp套接字发送一个int数组。我是否必须将其转换为字符数组或字节序列？什么是标准解决方案？

I have to send an int array over an udp socket. Do I have to convert it as char array or as a sequence of byte? What is the standard solution?

推荐答案

您可以按照以下步骤操作：

You could just do as follow:

int array[100] ;
sendto(sockfd, array, sizeof(array), 0, &addr, addrlen);

要在另一边收回你的数组（假设你总是发送相同大小的数组）：

To recv your array the other side (assuming you always send array of the same size):

int array[100] ;
recvfrom(sockfd, array, sizeof(array), 0, &addr, &addrlen);

正如评论中所说，你必须小心发送/接收系统的架构包。如果您正在为标准计算机开发应用程序，如果您想确定，则不应该有任何问题：

As said in the comments, you have to be carefull about the architecture of the system which send / receive the packet. If you're developping an application for 'standard' computers, you should not have any problem, if you want to be sure:

• 使用固定大小的类型（包括 stdint.h 并使用 int32_t 或者您需要的任何内容。


• 检查代码中的字典。

• Use a fixed-size type (include stdint.h and use int32_t or whatever is necessary for you.
• Check for endianess in your code.

Endianess转换：

Endianess conversion:

// SENDER   

int32_t array[100] = ... ;
int32_t arrayToSend[100] ;
for (int i = 0 ; i < 100 ; ++i) {
    arrayToSend[i] = htonl(array[i]) ;
}
sendto(sockfd, arrayToSend, sizeof(arrayToSend), 0, &addr, addrlen);

// RECEIVER

int32_t array[100] ;
int32_t arrayReceived[100] ;
recvfrom(sockfd, arrayReceived, sizeof(arrayReceived), 0, &addr, &addrlen);
for (int i = 0 ; i < 100 ; ++i) {
    array[i] = ntohl(arrayReceived[i]) ;
}

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