unsigned long int接受超出范围的值 [英] unsigned long int accepts out of range values

查看：210 发布时间：2018/8/6 20:07:54 c variables int range

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问题描述

这是我对此代码的第二个问题。
此代码来自Sams教你自己C编程第7版第66页的修改过的脚本。
将书籍复制出书后，我修改了它（只是一点点），使其更有趣。

This is my second question for this code. this code comes from a modified script on page 66 of "Sams Teach Yourself C Programming" 7th edition. After copying the script out of the book, I modified it (just a little) to make it more interesting.

I添加了一些额外的常量和变量，以使其能够接受更大的输入/输出值。

因为输入/输出是unsigned long int类型，其范围为0 - 2147483647，我将其设置为LIMIT。

然后我在程序的最后添加了一个else来处理超过该值的所有输入。我只是想做一个实验，看看它是否会注册，超出范围的值。

我第一次在代码中发布了一个关于数学错误的问题找我自己。这已经解决。

I added some additional constants and variables and such to enable it to accept a larger input/output value.
because the input/output is type "unsigned long int", which has a range of 0 - 2147483647, I set that to be the LIMIT.
Then I added an "else" at the very end of the program to deal with all inputs above that value. I just wanted to do an experiment to see if it would register, values that exceeded the range.
the first time I posted a question about a math error in the code that I had failed to find on my own. That was resolved.

以下是一些示例输出：

[bad_cat@KittyLitter LearningCode]$ gcc SamsC.04.seconds.c
[bad_cat@KittyLitter LearningCode]$ ./a.out
Enter the number of seconds ( > 0, < 2147483647 ): 
2147483646
2147483646 seconds is equal to 68 y 35 d, 3 h, 14 m, and 6 s
[bad_cat@KittyLitter LearningCode]$ ./a.out
Enter the number of seconds ( > 0, < 2147483647 ): 
2147483647
2147483647 seconds is equal to [bad_cat@KittyLitter LearningCode]$ ./a.out
Enter the number of seconds ( > 0, < 2147483647 ): 
2147483650
-2147483646 seconds is equal to error: -2147483646 is an excessive amount of seconds.
range for seconds must be between 0 and 2147483647!
If number of seconds exceeds 2147483647, then it is beyond range for type 'int'.
EXITING seconds program. 
[bad_cat@KittyLitter LearningCode]$ ./a.out
Enter the number of seconds ( > 0, < 2147483647 ): 
9876543210
1286608618 seconds is equal to 40 y 291 d, 7 h, 16 m, and 58 s
[bad_cat@KittyLitter LearningCode]$

以下是代码：

/* Illustrates the modulus operator. */
/* inputs a number of seconds, and converts to hours, minutes, and seconds. */
// minute = 60 seconds                  : 60
// hour = 60 * 60 seconds               : 3600
// day = 24 * 60 * 60 seconds           : 86400
// year = 365 * 24 * 60 * 60 seconds    : 31536000

#include <stdio.h>                                      // from original script

/* Define constants */

#define SECS_PER_MIN 60                                 // from original script
#define MIN_PER_HOUR 60
#define HOURS_PER_DAY 24
#define DAYS_PER_YEAR 365
#define SECS_PER_YEAR 31536000
#define SECS_PER_HOUR 3600                              // from original script
#define SECS_PER_DAY 86400
#define LIMIT 2147483647

unsigned seconds, minutes, hours, days, years, secs_remain, mins_remain, hours_remain, days_remain;     // modified from original script

int main(void)                                                                                          // from original script
{
    seconds = minutes = hours = days = years = secs_remain = mins_remain = hours_remain = days_remain = 0;
    /* Input the number of seconds. */

    printf( "Enter the number of seconds ( > 0, < %d ): \n", LIMIT );                  // modified from original script
    scanf( "%d", &seconds );                                                                            // from original script

    years = seconds /SECS_PER_YEAR;
    days = seconds / SECS_PER_DAY;
    hours = seconds / SECS_PER_HOUR;                                                                    // from original script
    minutes = seconds / SECS_PER_MIN;                                                                   // from original script
    days_remain = days % DAYS_PER_YEAR;
    hours_remain = hours % HOURS_PER_DAY;
    mins_remain = minutes % MIN_PER_HOUR;                                                               // modified from original script
    secs_remain = seconds % SECS_PER_MIN;                                                               // from original script

    printf( "%d seconds is equal to ", seconds );                                                       // from original script

    if ( seconds < SECS_PER_HOUR )
    {
         printf( "%d m, and %d s\n", minutes, secs_remain );
         return 0;
    }
         else if((seconds >= SECS_PER_HOUR ) && (seconds < SECS_PER_DAY ))
         {
              printf( "%d h, %d m, and %d s\n", hours, mins_remain, secs_remain );                  // from original script
              return 0;                                                                             // from original script
         }    
         else if((seconds >= SECS_PER_DAY ) && (seconds < SECS_PER_YEAR ))
         {
              printf( "%d d, %d h, %d m, and %d s\n", days, hours_remain, mins_remain, secs_remain );
              return 0;
         }            
         else if((seconds >= SECS_PER_YEAR ) && (seconds < LIMIT ))
         {
             printf( "%d y %d d, %d h, %d m, and %d s\n", years, days_remain, hours_remain, mins_remain, secs_remain );
             return 0;
         }   
         else if(seconds > LIMIT )
         {
             printf("error: %d is an excessive amount of seconds.\n", seconds);
             printf("range for seconds must be between 0 and %d!\n", LIMIT );
             printf("If number of seconds exceeds %d, then it is beyond range for type 'int'.\n", LIMIT );
             printf("EXITING seconds program. \n");
             return 1;
         }
    }

谢谢，我已将所有<code>％d更改为％u和限制。
我也将它们放在一起供将来参考：

Thanks, I've changed all "%d" to "%u" and Limit. I've also put this together for future reference:

#include <stdio.h>
#include <limits.h>

int main(void)
{
    printf("\n");

    printf("The number of bits in a byte =\t\t\t\t %d\n", CHAR_BIT);
    printf("The maximum number of bytes in a multi-byte character =\t %d\n", MB_LEN_MAX);

    printf("The minimum value of SIGNED CHAR =\t\t\t %d\n", SCHAR_MIN);
    printf("The maximum value of SIGNED CHAR =\t\t\t %d\n", SCHAR_MAX);
    printf("The maximum value of UNSIGNED CHAR =\t\t\t %d\n", UCHAR_MAX);

    printf("The minimum value of SHORT INT =\t\t\t %d\n", SHRT_MIN);
    printf("The maximum value of SHORT INT =\t\t\t %d\n", SHRT_MAX);
    printf("The maximum value for an UNSIGNED SHORT INT =\t\t %u\n", USHRT_MAX); 

    printf("The minimum value of INT =\t\t\t\t %d\n", INT_MIN);
    printf("The maximum value of INT =\t\t\t\t %d\n", INT_MAX);
    printf("The maximum value for an UNSIGNED INT =\t\t\t %u\n", UINT_MAX);

    printf("The minimum value of CHAR =\t\t\t\t %d\n", CHAR_MIN);
    printf("The maximum value of CHAR =\t\t\t\t %d\n", CHAR_MAX);

    printf("The minimum value of LONG =\t\t\t\t %ld\n", LONG_MIN);
    printf("The maximum value of LONG =\t\t\t\t %ld\n", LONG_MAX);
    printf("The maximum value for an UNSIGNED LONG INT =\t\t %Lu\n", ULONG_MAX);

    printf("\n");

    return(0);
}

unsigned long int接受超出范围的值 [英] unsigned long int accepts out of range values

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unsigned long int接受超出范围的值 [英] unsigned long int accepts out of range values

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