lua中整数的位数之和 [英] Sum of the digits of an integer in lua

问题描述

我看到了一个与Java和C相关的问题，但我使用的是LUA。答案可能适用于我，但我不理解它们。

I saw a question like this relating to Java and C, but I am using LUA. The answers might have applied to me, but I wasn't understanding them.

有人可以告诉我如何获得整数的各个数字的总和。
例如。

Could someone please tell me how I would get the sum of the individual digits of an Integer. For Example.

a = 275
aSum = 2+7+5

如果你能解释我将如何在LUA中实现这一点以及代码为什么会这样做，那将非常感激。

If you could explain how I would achieve this in LUA and why the code does what it does, that would be greatly appreciated.

推荐答案

真的是一个简单的功能。使用gmatch可以获得你需要去的地方。

Really a simple function. Using gmatch will get you where you need to go.

function sumdigits(str)
  local total = 0
  for digit in string.gmatch(str, "%d") do
  total = total + digit
  end
  return total
end

print(sumdigits(1234))

10

基本上，你是循环遍历整数并逐个拉出它们以将它们添加到总数中。 ％d仅表示一位数，因此string.gmatch（str，％d）表示每次匹配一位。 for是循环机制，因此对于字符串中的每个数字，它将添加到总数中。

Basically, you're looping through the integers and pulling them out one by one to add them to the total. The "%d" means just one digit, so string.gmatch(str, "%d") says, "Match one digit each time". The "for" is the looping mechanism, so for every digit in the string, it will add to the total.

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