将ascii字符转换为带符号的8位整数python [英] convert ascii character to signed 8-bit integer python

问题描述

这感觉应该很简单，但我找不到答案..

This feels like it should be very simple, but I haven't been able to find an answer..

在python脚本中我正在读取数据USB设备（USB鼠标的x和y移动）。它以单个ASCII字符到达。我可以使用ord轻松转换为无符号整数（0-255）。但是，我希望它是签名整数（-128到127） - 我该怎么做？

In a python script I am reading in data from a USB device (x and y movements of a USB mouse). it arrives in single ASCII characters. I can easily convert to unsigned integers (0-255) using ord. But, I would like it as signed integers (-128 to 127) - how can I do this?

任何帮助都非常感谢！非常感谢。

Any help greatly appreciated! Thanks a lot.

推荐答案

如果超过127则减去256：

Subtract 256 if over 127:

unsigned = ord(character)
signed = unsigned - 256 if unsigned > 127 else unsigned

或者，使用 struct 模块：

from struct import pack, unpack
signed = unpack('B', pack('b', unsigned))[0]

或直接来自角色：

signed = unpack('B', character)[0]

这篇关于将ascii字符转换为带符号的8位整数python的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！