整数的最后2位数？ Python 3 [英] Last 2 digits of an integer? Python 3

问题描述

使用我的代码，我想得到一个整数的最后两位数字。但是当我创建xa正数时，它将取前x个数字，如果是负数，它将删除前x个数字。

With my code, I want to get the last two digits of an integer. But when I make x a positive number, it will take the first x digits, if it is a negative number, it will remove the first x digits.

代码：

number_of_numbers = 1
num = 9
while number_of_numbers <= 100:
  done = False
  num = num*10
  num = num+1
  while done == False:
    num_last = int(repr(num)[x])
    if num_last%14 == 0:
      number_of_numbers = number_of_numbers + 1
      done = True
    else:
      num = num + 1
print(num)

推荐答案

为什么不提取数模100的绝对值？也就是说，使用

Why don't you extract the absolute value of the number modulus 100? That is, use

 abs(num) % 100 

提取最后两位数？

在性能和清晰度方面，这种方法很难被击败。

In terms of performance and clarity, this method is hard to beat.

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