.NET是BinaryReader在总是小尾数，即使在大端系统？ [英] Is .NET BinaryReader always little-endian, even on big-endian systems?

问题描述

BinaryReader在上微软文档ReadUnt32（例如）指出：读取使用小端编码当前流的4个字节的无符号整数。然而，就是这样总是正确的，即使在大端系统？

Microsoft documentation on BinaryReader for ReadUnt32 (for example) states: Reads a 4-byte unsigned integer from the current stream using little-endian encoding. However, is this always correct, even on big-endian systems?

推荐答案

该文件肯定是一个暗示，在其他平台上实现者应该使用小端编码和的Mono似乎尊重这个：

The documentation is certainly a hint that implementors on other platforms should use little-endian encoding, and Mono seems to respect this:

public virtual uint ReadUInt32() {
FillBuffer(4);

return((uint) (m_buffer[0] |
           (m_buffer[1] << 8) |
           (m_buffer[2] << 16) |
           (m_buffer[3] << 24)));
}

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