如何使用反射来查找实现特定接口的属性？ [英] How can I use reflection to find the properties which implement a specific interface?

问题描述

考虑这个例子：

public interface IAnimal
{
}

public class Cat: IAnimal
{
}

public class DoStuff
{
    private Object catList = new List<Cat>();

    public void Go()
    {
        // I want to do this, but using reflection instead:
        if (catList is IEnumerable<IAnimal>)
            MessageBox.Show("animal list found");

        // now to try and do the above using reflection...
        PropertyInfo[] properties = this.GetType().GetProperties();
        foreach (PropertyInfo property in properties)
        {
            //... what do I do here?
            // if (*something*)
                MessageBox.Show("animal list found");
        }
    }
}

你能否完成if语句用正确的代码替换某些东西？

Can you complete the if statement, replacing something with the correct code?

编辑：

我注意到我应该使用一个属性而不是一个字段才能工作，所以它应该是：

I noticed that I should have used a property instead of a field for this to work, so it should be:

    public Object catList
    {
        get
        {
          return new List<Cat>();
        }
    }

推荐答案

你可以查看属性' PropertyType ，然后使用 IsAssignableFrom ，我认为这是你想要的：

You can look at the properties' PropertyType, then use IsAssignableFrom, which I assume is what you want:

PropertyInfo[] properties = this.GetType().GetProperties();
foreach (PropertyInfo property in properties)
{
    if (typeof(IEnumerable<IAnimal>).IsAssignableFrom(property.PropertyType))
    {
        // Found a property that is an IEnumerable<IAnimal>
    }                           
}

当然，您需要为您的房产添加房产class，如果你想让上面的代码工作; - ）

Of course, you need to add a property to your class if you want the above code to work ;-)

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