如何声明实现类的java接口字段应该优化该字段 [英] how can I declare java interface field that implement class should refine that field

问题描述

如何声明实现类的java接口字段应该优化该字段？

How can I declare java interface field that implement class should refine that field ?

例如

public interface IWorkflow{
    public static final String EXAMPLE;// interface field 
    public void reject();
}

// and implement class
public class AbstWorkflow implements IWorkflow
{
    public static final String EXAMPLE = "ABCD"; /*MUST HAVE*/
    public void reject(){}
...
}

谢谢。

推荐答案

参见规范。接口中没有覆盖字段 - 它们只是隐藏在某些上下文中，而在其他上下文中则不明确。我只是远离。而是在接口中放置一个getter（getEXAMPLE（））

See section 9.3 of the specification. There is no overriding of fields in interfaces - they are just hidden in some contexts, and ambiguous in others. I'd just stay away. Instead put a getter in the interface (getEXAMPLE())

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