为什么嵌套接口隐式声明为静态？ [英] Why are nested interfaces declared implicitly static?

问题描述

正如标题所说，为什么嵌套接口是隐式静态的。为什么我不能像嵌套类一样使用嵌套接口，例如静态和无静态

解决方案

从 oracle文档：

内部类与其封闭类
的实例相关联，并且可以直接访问该对象的方法和字段

ie它保持对其封闭实例的引用。

另一个接口，它只是类型的静态定义。一个契约，用于提供一些多态性。

接口本身不能被实例化，因此它不能具有状态，因此它无法知道封闭的实例。 / p>

as the title says, why nested interfaces are implicitly static.Why cant i use nested interfaces just like nested classes ie like with static and without static

解决方案

From the oracle documentation:

an inner class is associated with an instance of its enclosing class and has direct access to that object's methods and fields

i.e. it maintains a reference to its enclosing instance.

An interface on the other and is just a static definition of type. A contract, used to provide some polymorphism.

An interface cannot itself be instantiated, therefor it cannot have state, and thus it cannot "know" about an enclosing instance.

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