从Android的web视图正常浏览器弹出打开链接 [英] Open link from Android Webview in normal browser as popup

问题描述

所以我有什么是basicly一个简单的WebView至极加载页面。这个页面有一个web视图中打开几个环节。这就是它应该做的，所以它的工作一切正常。

So what I have is basicly a simple webview wich loads a page. This page has a few links that opens within the webview. That's what it supposed to do, so it's working all fine.

但有一个从该页面至极应加载一个弹出式单条链路，所以我希望它在正常的浏览器中打开，当人们点击它。但正如我所说，各个环节都开设在web视图，以便链接，它也。

But there is one single link from that page wich should load as a popup, so I want it to open in the normal browser when people click it. But as I stated, all links are opening in the webview, so that link does it also.

我的问题是，我怎样才能使这个环节，在普通的浏览器作为一种弹出的打开？它甚至有可能？链接是可变的，所以它总是在变化，它不能应用在新的浏览器浏览器打开内很难codeD。

My question is, how can I make this link open in the normal browser as a kind of a popup? Is it even possible? The link is variable so it's changing always, it cannot be hardcoded within the application to open in a new browser browser.

谁能告诉我，如果这是可能的，怎么办呢？非常感谢！

Can someone tell me if it's possible and how to do it? Thank you very much!

推荐答案

下面是压倒一切的WebView加载一个例子，留在你的web视图中或离开：

Here's an example of overriding webview loading to stay within your webview or to leave:

import android.app.Activity;
import android.os.Bundle;
import android.webkit.WebView;
import android.webkit.WebViewClient;

public class TestWebViewActivity extends Activity {
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);


        WebView webView = (WebView) findViewById(R.id.webview);
        webView.setWebViewClient(new MyWebViewClient());
    }
}


class MyWebViewClient extends WebViewClient {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        if(url.contains("somePartOfYourUniqueUrl")){ // Could be cleverer and use a regex
            return super.shouldOverrideUrlLoading(view, url); // Leave webview and use browser
        } else {
            view.loadUrl(url); // Stay within this webview and load url
            return true;
        }
    }
}

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