Flask FileStorage对象到File对象 [英] Flask FileStorage object to File Object

问题描述

我已经通过 flask 提交了一个api，它提交了一个文件，在后端收到它之后，我想用python <$进一步将它上传到一个未知的服务器c $ c> requests module

I have made an api through flask which submit a file and after receiving it on the back end , I want to further upload this to an unknown server using python requests module

如果我这样做，服务器接受该文件 -

The server accepts the file if I do this like -

requests.post(urlToUnknownServer,files={'file':open('pathToFile')})

现在我的要求是通过烧瓶上传文件参数。

在烧瓶中我得到的文件是 FileStorage 对象。我不想在我的服务器上保存它，而是直接希望它进一步上传。

所以基本上我想将 FileStorage 对象转换为返回类型 open（）函数是 file （如果我错了请在这里纠正我）

Now my requirement is to get the file param uploaded through flask.
In flask I get the file as FileStorage object. I don't want to save this on my server, instead directly wants it to upload further.
So basically I want to convert that FileStorage object to return type of open() function which is file(please correct me here if I am wrong)

我曾尝试使用 -

obj=file(request.files['fileName'].read().encode('string-escape'))
requests.post(urlToUnknownServer,files={'file':obj})

这不起作用。可以在不保存我的服务器上的文件的情况下这样做。

This doesn't work. Can it be possible to do that without saving file on my server.

推荐答案

也许你可以使用read（）而无需编码。例如：

Maybe you can use read() without encoding it. such as this:

obj=request.files['fileName'].read()
requests.post(urlToUnknownServer,files={'file':obj})

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