二进制搜索具有未知行长度的巨大文件 [英] Binary search over a huge file with unknown line length

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本文介绍了二进制搜索具有未知行长度的巨大文件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用庞大的数据CSV文件。每个文件包含数百万条记录,每条记录都有一个密钥。记录按其密钥排序。我不想在搜索certian数据时查看整个文件。
我见过这个解决方案:用Python阅读巨大的文件

I'm working with huge data CSV file. Each file contains milions of record , each record has a key. The records are sorted by thier key. I dont want to go over the whole file when searching for certian data. I've seen this solution : Reading Huge File in Python

但是它表明你在文件上使用相同长度的行 - 在我的情况下不支持。

But it suggests that you use the same length of lines on the file - which is not supported in my case.

我想在每行添加一个填充然后保持一个固定的行长度,但我想知道是否有更好的方法。

I thought about adding a padding to each line and then keeping a fixed line length , but I'd like to know if there is a better way to do it.

我正在使用python

I'm working with python

推荐答案

您不必拥有固定宽度记录,因为您不必执行此操作面向记录的搜索。相反,您可以只进行面向字节的搜索,并确保在进行搜索时重新对齐键。这是一个(可能是错误的)示例,说明如何修改链接到从面向记录到面向字节的解决方案:

You don't have to have a fixed width record because you don't have to do a record-oriented search. Instead you can just do a byte-oriented search and make sure that you realign to keys whenever you do a seek. Here's a (probably buggy) example of how to modify the solution you linked to from record-oriented to byte-oriented:

bytes = 24935502 # number of entries
for i, search in enumerate(list): # list contains the list of search keys
  left, right = 0, bytes - 1 
  key = None
  while key != search and left <= right:
    mid = (left + right) / 2
    fin.seek(mid)
    # now realign to a record
    if mid:
        fin.readline()
    key, value = map(int, fin.readline().split())
    if search > key:
      left = mid + 1
    else:
      right = mid - 1
  if key != search:
    value = None # for when search key is not found
  search.result = value # store the result of the search

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