从C＃运行.bat文件 [英] Run .bat file from C#

问题描述

我面临一个奇怪的问题，我有一个.bat文件，其中包含一个重命名文件的代码，当我手动打开.bat文件时，它会执行它所写的重命名文件，但是当我尝试从C＃以程序方式打开它，它没有做任何事情，它jsut打开文件并且不编译它写入的内容。我键入了该代码：

i am facing a strange issue , i have a .bat file which contains a code for renaming a file , when i open the .bat file manually it does what it is written on it which is renaming a file , but when i try to open it programtically from C# , it doesnt do anything , it jsut open the file and do not compile what it is written into . i typed that code :

Process.Start(@"file.bat");

我也知道如果你输入cmd的路径并按下输入它将打开文件并编译它，所以我写道：

I also knew if you typed the path into cmd and pressed enter it will open the file and compile it , so i wrote that :

ProcessStartInfo psi3 = new ProcessStartInfo("cmd", "/c " + '"'+"D:\\my Work\\My Soft\\CA Delete\\CA Delete\\bin\\Debug\\file.bat"+'"');
Process p3 = Process.Start(psi3);
p3.WaitForExit()

但问题仍然存在：文件正在打开但是永远都不会写入它。

But still the same issue : the file is being opened but never does what it is written into it.

编辑：[我想为什么]

EDIT : [I Figured why]

我拍了一下应该运行.bat文件的CMD窗口的镜头，我得到了错误：

I took a snap shot of the CMD windows that should run the .bat file and i got ERROR :

ERROR : THE FILE SPECIFIED COULD NOT BE FOUND

但是怎么样？当我手动运行.bat文件时，它可以正常运行!!!

but how ? when i run the .bat file manually it works FINE!!!

推荐答案

这应该适合你：

String myBatchFileName = "name_of_file.bat";
System.Diagnostics.Process.Start(myBatchFileName);

• 注意变量 myBatchFileName 是.bat文件的实际名称.....


• Note that variable myBatchFileName is the actual name of .bat file.....

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