在XML文件搜索与XPath的Andr​​oid中 [英] Search in XML File with XPath in Android

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本文介绍了在XML文件搜索与XPath的Andr​​oid中的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我的深化发展的应用程序在Android上!

I'm developping an application on android!

嗯,我有一个小冲突,现在,我想执行一个XPath查询,但我没有到达来解决这个问题。

Well I have a little conflict now, I want to execute an XPath query but I didn't arrive to solve this problem.

该XML的filethat我用一个例子:

This an example of XML filethat I use:

<?xml version="1.0"?>
<catalog>
  <book id="bk101">
   <author>Gambardella, Matthew</author>
 <title>XML Developer's Guide</title>
 <genre>Computer</genre>
 <price>44.95</price>
 <publish_date>2000-10-01</publish_date>
 <description>An in-depth look at creating applications 
  with XML.</description>
</book>

<book id="bk102">
 <author>Ralls, Kim</author>
 <title>Midnight Rain</title>
 <genre>Fantasy</genre>
 <price>5.95</price>
 <publish_date>2000-12-16</publish_date>
 <description>A former architect battles corporate zombies, 
  an evil sorceress.</description>
</book>

<book id="bk103">
 <author>Corets, Eva</author>
 <title>Maeve Ascendant</title>
 <genre>Fantasy</genre>
 <price>5.95</price>
 <publish_date>2000-11-17</publish_date>
 <description>After the collapse of a nanotechnology 
  society in England.</description>
 </book>
 </catalog>

我该怎么办??

How can I do??

在此先感谢!

推荐答案

请看下面的例子:

import java.io.FileReader;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Element;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
public class GuestList {
  public static void main(String[] args) throws Exception {
    XPathFactory factory = XPathFactory.newInstance();
    XPath xPath = factory.newXPath();
    NodeList shows = (NodeList) xPath.evaluate("/schedule/show", new InputSource(new FileReader(
        "tds.xml")), XPathConstants.NODESET);
    for (int i = 0; i < shows.getLength(); i++) {
      Element show = (Element) shows.item(i);
      String guestName = xPath.evaluate("guest/name", show);
      String guestCredit = xPath.evaluate("guest/credit", show);
      System.out.println(show.getAttribute("weekday") + ", " + show.getAttribute("date") + " - "
          + guestName + " (" + guestCredit + ")");
    }
  }
}

的例子其余的都是在这里: http://jexp.ru/index.php / Java_Tutorial / XML / XPath的

这篇关于在XML文件搜索与XPath的Andr​​oid中的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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