XMPPFramework - 实施群聊（MUC） [英] XMPPFramework - Implement Group Chat (MUC)

问题描述

我正在使用iOS聊天客户端。有谁可以帮助我进行多用户聊天？

I am working on the iOS chat client. Can anyone please help me with the Multi-User Chat?

我已经实施了Robbiehanson的XMPPFramework。

I have implemented Robbiehanson's XMPPFramework.

任何人都可以请告诉我如何获取组列表并使用此框架在服务器中创建一个组？

Can anyone please let me know how to get list of group and create a group in server with this framework?

提前致谢。

推荐答案

获取房间列表：

NSString* server = @"chat.shakespeare.lit"; //or whatever the server address for muc is
XMPPJID *servrJID = [XMPPJID jidWithString:server];
XMPPIQ *iq = [XMPPIQ iqWithType:@"get" to:servJID];
[iq addAttributeWithName:@"from" stringValue:[xmppStream myJID].full];
NSXMLElement *query = [NSXMLElement elementWithName:@"query"];
[query addAttributeWithName:@"xmlns" stringValue:@"http://jabber.org/protocol/disco#items"];
[iq addChild:query];
[xmppStream sendElement:iq];

检查代理方法中的响应：

- (BOOL)xmppStream:(XMPPStream *)sender didReceiveIQ:(XMPPIQ *)iq{
    DDLogVerbose(@"%@", [iq description]);
    return NO;
}

加入或创建空间

XMPPRoomMemoryStorage * _roomMemory = [[XMPPRoomMemoryStorage alloc]init];
NSString* roomID = @"[e-mail]";
XMPPJID * roomJID = [XMPPJID jidWithString:roomID];
XMPPRoom* xmppRoom = [[XMPPRoom alloc] initWithRoomStorage:_roomMemory
                                             jid:roomJID
                                   dispatchQueue:dispatch_get_main_queue()];
[xmppRoom activate:self.xmppStream];
[xmppRoom addDelegate:self delegateQueue:dispatch_get_main_queue()];
[xmppRoom joinRoomUsingNickname:@"myNickname"
                        history:nil
                       password:nil];

检查XMPPRoom委托方法中的响应：

- (void)xmppRoomDidCreate:(XMPPRoom *)sender{
    DDLogVerbose(@"%@: %@", THIS_FILE, THIS_METHOD);
}

- (void)xmppRoomDidJoin:(XMPPRoom *)sender{
    DDLogVerbose(@"%@: %@", THIS_FILE, THIS_METHOD);
}

更新

配置房间：

之后：

[xmppRoom joinRoomUsingNickname:self.xmppStream.myJID.user
                        history:history
                       password:nil];

add：

[xmppRoom fetchConfigurationForm];

并检查回复：

- (void)xmppRoom:(XMPPRoom *)sender didFetchConfigurationForm:(NSXMLElement *)configForm{
    DDLogVerbose(@"%@: %@ -> %@", THIS_FILE, THIS_METHOD, sender.roomJID.user);
}

查看 configForm 对象，并根据需要进行更改，然后使用 [sender configureRoomUsingOptions：newConfig];

Review the configForm object, and change as needed, then send it with [sender configureRoomUsingOptions:newConfig];

示例发送：
更改配置以使房间持久，您可以添加以下内容：

example: to change the configuration to make the room persistent you can add something like:

NSXMLElement *newConfig = [configForm copy];
NSArray* fields = [newConfig elementsForName:@"field"];
for (NSXMLElement *field in fields) {
    NSString *var = [field attributeStringValueForName:@"var"];
    if ([var isEqualToString:@"muc#roomconfig_persistentroom"]) {
        [field removeChildAtIndex:0];
        [field addChild:[NSXMLElement elementWithName:@"value" stringValue:@"1"]];
    }
}
[sender configureRoomUsingOptions:newConfig];

（我不熟悉NSXMLElement，所以可能有更好的方法来更改值）

(i'm not familiar with NSXMLElement, so maybe there is a better way to change the value)

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