如何为UITableViewCell显示自定义UIMenuItem？ [英] How to show a custom UIMenuItem for a UITableViewCell?

问题描述

我希望当我长按UITableViewCell以显示自定义UIMenuItems时弹出UIMenuController。

I want the UIMenuController that pops up when I long-press a UITableViewCell to show custom UIMenuItems.

我在viewDidLoad中设置了自定义项

I set up the custom item in viewDidLoad

UIMenuItem *testMenuItem = [[UIMenuItem alloc] initWithTitle:@"Test" action:@selector(test:)];
[[UIMenuController sharedMenuController] setMenuItems: @[testMenuItem]];

然后我设置所有正确的委托方法。

And then I set all the right delegate methods.

- (BOOL)tableView:(UITableView *)tableView shouldShowMenuForRowAtIndexPath:(NSIndexPath *)indexPath {
    return YES;
}

-(BOOL)tableView:(UITableView *)tableView canPerformAction:(SEL)action forRowAtIndexPath:(NSIndexPath *)indexPath withSender:(id)sender {
    return (action == @selector(copy:) || action == @selector(test:));
}

- (BOOL)tableView:(UITableView *)tableView performAction:(SEL)action forRowAtIndexPath:(NSIndexPath *)indexPath withSender:(id)sender {
    if (action == @selector(copy:)) {
         // do stuff
    }

    return YES;
}

但它只是显示复制项目，因为我只允许它和我的自定义项目。但是，自定义项目不会显示。

But all it does, is show the "Copy" item, since I only allow it and my custom item. The custom item, however, won't show up.

我意识到，我可以为细胞本身添加一个手势识别器，但这种方法会失败的目的。 UIMenuController的共享实例，不是吗？

I realize, I could add a gesture recognizer to the cell itself, but that kind of defeats the purpose of the shared instance of UIMenuController, doesn't it?

推荐答案

据我所知，有两个主要问题：

As far as I understand there are two main problems:

1）你希望 tableView canPerformAction：支持自定义选择器，而文档说它只支持两个 UIResponderStandardEditActions （复制和/或粘贴）;

1) you expect tableView canPerformAction: to support custom selectors while the documentation says it supports only two of UIResponderStandardEditActions (copy and/or paste);

2）不需要零件 || action == @selector（test :) ，因为您要通过初始化 menuItems 属性来添加自定义菜单选项。对于此项目选择器，检查将是自动的。

2) there's no need for the part || action == @selector(test:) as you are adding the custom menu options by initializing menuItems property. For this items selectors the check will be automatical.

您可以做什么来显示自定义菜单项并且工作是：

What you can do to get the custom menu item displayed and work is:

1）修复表格视图委托方法

1) Fix the table view delegate methods with

a）

UIMenuItem *testMenuItem = [[UIMenuItem alloc] initWithTitle:@"Test" action:@selector(test:)];
[[UIMenuController sharedMenuController] setMenuItems: @[testMenuItem]];
[[UIMenuController sharedMenuController] update];

b）

- (BOOL)tableView:(UITableView *)tableView shouldShowMenuForRowAtIndexPath:(NSIndexPath *)indexPath {
    return YES;
}

-(BOOL)tableView:(UITableView *)tableView canPerformAction:(SEL)action forRowAtIndexPath:(NSIndexPath *)indexPath withSender:(id)sender {
    return (action == @selector(copy:));
}

- (void)tableView:(UITableView *)tableView performAction:(SEL)action forRowAtIndexPath:(NSIndexPath *)indexPath withSender:(id)sender {
    // required
}

2）设置单元格（子类化 UITableViewCell ）

2) Setup the cells (subclassing UITableViewCell) with

-(BOOL) canPerformAction:(SEL)action withSender:(id)sender {
    return (action == @selector(copy:) || action == @selector(test:));
}

-(BOOL)canBecomeFirstResponder {
    return YES;
}

/// this methods will be called for the cell menu items
-(void) test: (id) sender {

}

-(void) copy:(id)sender {

}
///////////////////////////////////////////////////////

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