在NSString中查找子字符串的所有位置（不仅仅是第一个） [英] Find all locations of substring in NSString (not just first)

问题描述

字符串中有一个子字符串多次出现。我使用 rangeOfString ，但它似乎只能找到第一个位置。如何查找子字符串的所有位置？

There is a substring that occurs in a string several times. I use rangeOfString, but it seems that it can only find the first location. How can I find all the locations of the substring?

NSString *subString1 = @"</content>";
NSString *subString2 = @"--\n";
NSRange range1 = [newresults rangeOfString:subString1];
NSRange range2 = [newresults rangeOfString:subString2];
int location1 = range1.location;
int location2 = range2.location;
NSLog(@"%i",location1);
NSLog(@"%i",location2);

推荐答案

您可以使用 rangeOfString： options：range：并将第三个参数设置为超出第一个参数的范围。例如，你可以这样做：

You can use rangeOfString:options:range: and set the third argument to be beyond the range of the first occurrence. For example, you can do something like this:

NSRange searchRange = NSMakeRange(0,string.length);
NSRange foundRange;
while (searchRange.location < string.length) {
    searchRange.length = string.length-searchRange.location;
    foundRange = [string rangeOfString:substring options:nil range:searchRange];
    if (foundRange.location != NSNotFound) {
        // found an occurrence of the substring! do stuff here
        searchRange.location = foundRange.location+foundRange.length;
    } else {
        // no more substring to find
        break;
    }
}

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