如何以编程方式获取iOS的字母数字版本字符串 [英] How to programmatically get iOS's alphanumeric version string

问题描述

我一直在使用漂亮的 PLCrashReport 框架向我的服务器发送崩溃来自我用户的iOS设备的报告。

I've been working with the nice PLCrashReport framework to send to my server the crash reports from my user's iOS devices.

但是，为了表示崩溃报告， symbolicatecrash 实用程序会请求iPhone OS版本号，我有ipsw的字母数字版本，格式为：

However, to symbolicate the crash report, the symbolicatecrash utility requests that along with the iPhone OS version number, I have the ipsw's alphanumeric version, in the form of:

OS Version:      iPhone OS 4.0.1 (8A293)

我知道我可以通过 [[UIDevice currentDevice] systemVersion]获取iOS的数字版本，但我怎样才能得到另一个呢？

I know that I can get the iOS's numeric version by [[UIDevice currentDevice] systemVersion], but how can I get the other one?

我找不到方法，而且我已经搜遍了我想象的任何地方。

I can't find a way, and I've searched everywhere I could imagine.

推荐答案

不确定为什么其他人说这是不可能的，因为它使用 sysctl 函数。

Not sure why others are saying that this is not possible because it is using the sysctl function.

#import <sys/sysctl.h>    

- (NSString *)osVersionBuild {
    int mib[2] = {CTL_KERN, KERN_OSVERSION};
    u_int namelen = sizeof(mib) / sizeof(mib[0]);
    size_t bufferSize = 0;

    NSString *osBuildVersion = nil;

    // Get the size for the buffer
    sysctl(mib, namelen, NULL, &bufferSize, NULL, 0);

    u_char buildBuffer[bufferSize];
    int result = sysctl(mib, namelen, buildBuffer, &bufferSize, NULL, 0);

    if (result >= 0) {
        osBuildVersion = [[[NSString alloc] initWithBytes:buildBuffer length:bufferSize encoding:NSUTF8StringEncoding] autorelease]; 
    }

    return osBuildVersion;   
}

这篇关于如何以编程方式获取iOS的字母数字版本字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！