在iOS中使用NSJSONSerialization进行JSON解析 [英] JSON parsing using NSJSONSerialization in iOS
问题描述
我在我的代码中解析 JSON 。但是在检索解析的 JSON 的数据时，我遇到了一些意想不到的问题。所以让我解释一下我的问题。
I am parsing a JSON in my code. But I am getting some unexpected issues while retrieving data of parsed JSON. So let me explain my problem.
我必须使用xcode解析 JSON 数据。当我在浏览器中点击相同的URL时，这就是要解析的数据：
I have to parse following JSON data using xcode. This is what data to be parsed looks like while I hit same URL in browser:
{
"RESPONSE":[
{"id":"20",
"username":"john",
"email":"abc@gmail.com",
"phone":"1234567890",
"location":"31.000,71.000"}],
"STATUS":"OK",
"MESSAGE":"Here will be message"
}
我的代码达到此 JSON 数据如下：
My code to reach up to this JSON data is as follow:
NSData *data = [NSData dataWithContentsOfURL:finalurl];
NSError *error;
NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
如果我使用<$打印对象 json c $ c> NSLog ，即 NSLog（@json：％@，[json description]）; 它看起来像：
If I print object json using NSLog, i.e. NSLog(@"json: %@", [json description]); it looks like:
json: {
MESSAGE = "Here will be message";
RESPONSE =(
{
email = "abc@gmail.com";
id = 20;
location = "31.000,71.000";
phone = 1234567890;
username = john;
}
);
STATUS = OK;
}
所以，在这里我发现了两件事：
So, here I observed two things:
-
密钥（或节点）的顺序（
MESSAGE，RESPONSE 和STATUS）已更改。
RESPONSE 包含在'（'&'）'大括号中。
现在，如果我将键的值分开 MESSAGE & ; STATUS 和 NsLog ，然后将它们打印为正确的字符串。
Now if I separate out values for keys MESSAGE & STATUS and NsLog them, then they get printed as proper string.
喜欢 msgStr：这里有消息& 状态：确定
但如果我将电子邮件和用户名 ，然后我无法将其作为字符串。
But if I separate out value for RESPONSE as a dictionary and again separating sub values of that dictionary like email and username, then I can't getting those as string.
以下是我写的代码：
NSMutableDictionary *response = [json valueForKey:@"RESPONSE"];
NSString *username = [response valueForKey:@"username"];
NSString *emailId = [response valueForKey:@"email"];
如果我打印用户名和 emailId ，然后他们没有打印成普通字符串，而是输出为：
If I print username and emailId, then they are not getting printed as normal string, instead it outputs as:
username:(
john
)
email:(
abc@gmail.com
)
所以我的问题是为什么它不是正常的字符串？如果我尝试进一步使用这些变量，那么它们会显示在'（'&'）'括号内的值。这是因为 NSJSONSerialization 吗？
So my question is why it's not getting as a normal string? If I tried to use this variables further then they show value enclosed within '(' & ')' braces. Is this happening because of NSJSONSerialization?
推荐答案
首先在你的 JSON 回复词典，在键' RESPONSE '下你有一个数组而不是字典，该数组包含字典对象。
所以要提取用户名和电子邮件ID ，如下所示
First of all in your JSON response dictionary, under the key 'RESPONSE' you have a array not a dictionary and that array contains dictionary object.
So to extract username and email ID so as below
NSMutableDictionary *response = [[[json valueForKey:@"RESPONSE"] objectAtIndex:0]mutableCopy];
NSString *username = [response valueForKey:@"username"];
NSString *emailId = [response valueForKey:@"email"];
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