NSCountedSet - 获取集合中的项目数 [英] NSCountedSet - get count of items in set

问题描述

我有一个信息数组，其中包含多个我要匹配的名称，然后计数，然后移动到表格视图，就像您在消息应用中看到的那样。

I have a array of info that has multiple Names that I want to match and count then move to a table view such as you would see on a messages app.

我已达到这一点。我可以在哪里记录并查看我想要的内容，但根本无法找到任何解决方案从该集中提取该信息并相应地放入 tableview 。

I have reached to this point. Where I can log and see what I want but simply can not find any solution pulling that info from the set and placing into a tableview accordingly.

示例

- (void)directMessagesReceived:(NSArray *)messages forRequest:(NSString    
*)connectionIdentifier{

for(NSDictionary *d in messages) {

  // NSLog(@"See Direct Messageges Parsing Info: %@", d);

    Tweet *tweetDic = [[Tweet alloc] initWithTweetDictionary:d];


    //[directMessages addObject:tweetDic];
    [tweetDic autorelease];



}

//[arayToScan addObject:[messages valueForKey:@"sender_screen_name"]];
[arayToScan addObjectsFromArray:messages];
[self checkForDuplicateIDs]; 
// NSLog(@"Same ScreenName Received: %@", arayToScan);

//[self.mainTableView reloadData];    
 NSLog(@"DM COUNT = %i",[directMessages count]);

[DSBezelActivityView removeViewAnimated:YES];


}



- (NSSet *)checkForDuplicateIDs {

//CHECK FOR DUPLICATES IN ARRAY
NSArray *allIDs = [arayToScan valueForKeyPath:@"sender_screen_name"];
NSArray *sortedIDs = [allIDs sortedArrayUsingSelector:@selector(compare:)];

NSString *previousID = nil;
duplicateIDs = [NSMutableSet set];
for (NSString *anID in sortedIDs) {
    if ([previousID isEqualToString:anID]) {
        [duplicateIDs addObject:anID];

    }
    previousID = anID;
}


//THEN REMOVE ANY DUPLICATES IN NEW ARRAY
NSCountedSet *countedSet = [NSCountedSet setWithArray:sortedIDs];
NSMutableArray *oneMess = [NSMutableArray arrayWithCapacity:[sortedIDs count]];
NSMutableArray *multipleMess = [NSMutableArray arrayWithCapacity:[sortedIDs count]];


for(id obj in countedSet) {
    if([countedSet countForObject:obj] == 1) {
        [oneMess addObject:obj];
    }
 for(id duplicatenames in countedSet) {
     if ([countedSet countForObject:duplicatenames]>1) {
         [multipleMess addObject:duplicatenames];
         [countedSet  countForObject:duplicatenames];

     }


}


}
//NSLog(@"NSCountedSet = %@",[countedSet allObjects]);
 //NSLog(@"NSCountedSet = %@",countedSet);
//NSLog(@"One Message = %@",oneMess);
// NSLog(@"Multiple Messages = %@",multipleMess);


//HERE I HAVE ORIGINAL ARRAY IN ALBETICAL ORDER
// NSLog(@"Messages Containing more then 1 = %@",sortedIDs);    

//HERE I HAVE DUPLICATES IN ALBETICAL ORDER
// NSLog(@"Messages Containing more then 1 = %@",duplicateIDs);

//HERE I HAVE THE MESSAGES ONLY CONTAING 1
//NSLog(@"Messages Containing only 1 = %@",oneMess);


//NOW I WANT TO COUNT THE DUPLICATES TO PLACE AS A STRING IN CELL FOR # OF MESSAGES & #   
OF ROW IN TBLVIEW
//NSLog(@"Duplicates count = %i",[duplicateIDs count]);
// NSLog(@"Messages Containing only count = %i",[oneMess count]);

//HERE I WOULD ADD BOTH ARRAYS AND SEND TO MY ARRAY BELOW WHICH IS USED FOR MY TBLVIEW
THIS INFO IS RETRIEVABLE WHAT I NEED IS THE # OF EACH DUPLICATE AS SEEN 

//ARRAY *NEWARRAY INIT WITH OBJECTS ,ONEMESS, MULTIPLEMESS,
//ARRAY CUSTOM # OF EACH MULTIPLE MESSAGE TO SHOW IN TBLVIEW???

 //THEN I CAN CONTINUE WITH THE BELOW METHOD TO RELOD THE TABLEVIEW
//[directMessages addObject:NEWARRAY];
//[self.mainTableView reloadData];


return [[duplicateIDs copy] autorelease];

}

这是日志......这种情况多次发生因为它很重要，但我只是记录它，看它是否正常工作。任何帮助将不胜感激

This is the log... this happens as many times as it counts but I just logged it to see if it was working which its is. Any help would be greatly appreciated

Counted = <NSCountedSet: 0x6d8cb80> (Nkapoor124 [33], iphonetechtips [3], jima6636 [4], pro1995 [2], iphone266 [2], eenofonn [1], iphoneMaster323 [3], FreeAppl3 [2], Bababooey13 [7], _CL1CK_ [5], _ToyVan_ [4], Nucleiosis [26], dracossaint [6], AlexInHouston [1], FlybriTn [7], iOSGraphix [1], deckedsg [5], 19est80 [3], JHackstar [2], barsoverbeats [7], anonomys209 [5], 87whitestallion [1], bAdGigabit [55], Sgt_Impacto [3], Nazaroth [2], K_Nitsua [1], MannyIphone [6], iphoneman76 [3])

推荐答案

在您的澄清中，您询问了每份副本的金额（数量？）。你可以得到下面的计数。如果你正在寻找每个重复的次数（而不是每个的总数）那么这个数量 - 每个都是1。如果它是计数 - 1是0，则没有重复。

In your clarification, you asked for the amount (number?) of each duplicate. You can get at the count below. If you're looking for the number of times each is duplicated (instead of total count of each) then that's count - 1 for each. If it's count - 1 is 0, there's no duplicates.

我认为你正在寻找NSCountedSet countForObject方法。

I think you're looking for NSCountedSet countForObject method.

以下示例......

The sample below ...

    NSArray *names = [NSArray arrayWithObjects:@"John", @"Jane", @"John", nil];
    NSCountedSet *set = [[NSCountedSet alloc] initWithArray:names];

    for (id item in set)
    {
        NSLog(@"Name=%@, Count=%lu", item, (unsigned long)[set countForObject:item]);
    }

将输出：

2011-09-30 01:00:50.665 Craplet[7854:707] Name=Jane, Count=1
2011-09-30 01:00:50.679 Craplet[7854:707] Name=John, Count=2

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