如何从WebViewClient打开新的浏览器? [英] How to open new browser from WebViewClient?
本文介绍了如何从WebViewClient打开新的浏览器?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
短的问题,我不能让我的手指上,我想推出一个新的浏览器从我的WebView人后单击超链接。但是,我怎么可以设置该链接逃离WebViewClient的这个目标?
下面是我的code,任何帮助是极大的AP preciated:
的WebView网站=(web视图)findViewById(R.id.WebView);
site.setWebViewClient(新WebViewClient());
site.setScrollBarStyle(View.SCROLLBARS_INSIDE_OVERLAY);
site.getSettings()setJavaScriptEnabled(真)。
button1.setOnClickListener(button1OnClickListener);
button2.setOnClickListener(button2OnClickListener);
button3.setOnClickListener(button3OnClickListener);
button4.setOnClickListener(button4OnClickListener);
最后AlertDialog alertDialog =新AlertDialog.Builder(本).create();
进度= ProgressDialog.show(FlitsersActivity.this,Thingy1,载入...,假的,真正的);
site.setWebViewClient(新WebViewClient(){
公共布尔shouldOverrideUrlLoading(web视图查看,字符串URL){
Log.i(TAG,正在加载...);
view.loadUrl(URL);
返回true;
}
公共无效onPageFinished(web视图查看,字符串URL){
Log.i(TAG,完成:+网址);
如果(progressBar.isShowing()){
progressBar.dismiss();
}
}
公共无效onReceivedError(web视图来看,INT错误code,字符串描述,字符串failingUrl){
Log.e(TAG,错误:+说明);
Toast.makeText(MyActivity.this,哦,不!+描述,Toast.LENGTH_SHORT).show();
alertDialog.setTitle(错误);
alertDialog.setMessage(介绍);
alertDialog.setButton(OK,新DialogInterface.OnClickListener(){
公共无效的onClick(DialogInterface对话,诠释它){
返回;
}
});
alertDialog.show();
}
});
site.loadUrl(http://www.etcetera.com);
}
解决方案
没错,谢谢!我想我找到了你周围写的第二个响应的时间;)
现在,我使用code以下:它就像一个魅力:)非常感谢你的回应
! site.setWebViewClient(新WebViewClient(){
公共布尔shouldOverrideUrlLoading(web视图查看,字符串URL){
字符串myAlternativeURL =HTTP://的newURL;
如果(!url.equals(myAlternativeURL)){
{
意图I =新的意图(Intent.ACTION_VIEW);
i.setData(Uri.parse(的http://的newURL));
startActivity(ⅰ);
}
返回true;
} 其他 {
Log.i(TAG,正在加载...);
view.loadUrl(URL);
返回true;
}
}
Short question that i cannot get my finger on, i'd like to launch a new browser from my WebView after people click a hyperlink. But how can i set that target of that link to escape the WebViewClient??
Here's my code, any help is greatly appreciated:
WebView site = (WebView)findViewById(R.id.WebView);
site.setWebViewClient(new WebViewClient());
site.setScrollBarStyle(View.SCROLLBARS_INSIDE_OVERLAY);
site.getSettings().setJavaScriptEnabled(true);
button1.setOnClickListener(button1OnClickListener);
button2.setOnClickListener(button2OnClickListener);
button3.setOnClickListener(button3OnClickListener);
button4.setOnClickListener(button4OnClickListener);
final AlertDialog alertDialog = new AlertDialog.Builder(this).create();
progressBar = ProgressDialog.show(FlitsersActivity.this, "Thingy1", "Load...", false, true);
site.setWebViewClient(new WebViewClient() {
public boolean shouldOverrideUrlLoading(WebView view, String url) {
Log.i(TAG, "Loading...");
view.loadUrl(url);
return true;
}
public void onPageFinished(WebView view, String url) {
Log.i(TAG, "Done: " +url);
if (progressBar.isShowing()) {
progressBar.dismiss();
}
}
public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) {
Log.e(TAG, "Error: " + description);
Toast.makeText(MyActivity.this, "Oh no! " + description, Toast.LENGTH_SHORT).show();
alertDialog.setTitle("Error");
alertDialog.setMessage(description);
alertDialog.setButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
return;
}
});
alertDialog.show();
}
});
site.loadUrl("http://www.etcetera.com");
}
解决方案
Exactly, thanks! I think i found out around the time you wrote the second response ;)
Right now i am using the code below: it works like a charm :) Thank you very much for responding!
site.setWebViewClient(new WebViewClient() {
public boolean shouldOverrideUrlLoading(WebView view, String url) {
String myAlternativeURL = "http://newURL";
if (!url.equals(myAlternativeURL)) {
{
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse("http://newURL"));
startActivity(i);
}
return true;
} else {
Log.i(TAG, "Loading...");
view.loadUrl(url);
return true;
}
}
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