如何在视图控制器中创建后退按钮以转到父视图控制器 [英] How to create a back button in a view controller to go to parent view controller

问题描述

嗨我有一个带有容器的视图控制器，并且在容器中有一个带有集合视图的子视图，当用户点击集合视图单元时，它将我发送给详细视图控制器，但现在我要做的是添加一个返回我的详细视图控制器中的按钮，它将我发送到parentViewController

hi I have a view controller with a container and in the container a child view with a collection view when the user taps the collection view cell it sends me to detail view controller but now what i want to do is to add a back button in my detail view controller which sends me to the parentViewController

推荐答案

案例1 ：放松Segue

根据您的具体情况，这将完美无缺：

This will work perfect according to your situation:

iOS Unwind Segue

Unwind Segues为您提供了一种展开导航堆栈并指定要返回的目的地的方法。

Unwind Segues give you a way to "unwind" the navigation stack and specify a destination to go back to.

案例2 ：PopToRootViewController

Case 2 : PopToRootViewController

如果您的父视图也是您的根视图控制器，然后您可以使用轻松取回popToRootViewControllerAnimated：YES 。

If you Parent view is also your Root view controller, then you can easily get back using popToRootViewControllerAnimated:YES.

创建自己的后退按钮将其添加到导航栏方法 backButtonTouch 。

Create own back button add it to navigation bar with method backButtonTouch.

self.navigationItem.leftBarButtonItem = [[UIBarButtonItem alloc] initWithTitle:NSLocalizedString(@"Back", nil) style:UIBarButtonItemStyleDone target:self action:@selector(backButtonTouch:)]; 

将以上代码添加到 viewDidLoad 。

-(void)backButtonTouch:(id)sender{
    [self.navigationController popToRootViewControllerAnimated:YES];
}

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