for循环CGFloat出错 [英] Error in for loop CGFloat

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本文介绍了for循环CGFloat出错的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我将项目从Swift 2转换为Swift 3,现在我在以下行中收到错误:

I converted a project from Swift 2 to Swift 3 and now I get an error in the following line:

for i:CGFloat in 0 ..< 2.0 + self.frame.size.width / ( skyTexture.size().width * 2.0 ) += 1 {

表示:变异运算符的左侧不可变'..<'返回不可变值

let skyTexture = SKTexture(imageNamed: "sky")
    skyTexture.filteringMode = .nearest

    let moveSkySprite = SKAction.moveBy(x: -skyTexture.size().width * 2.0, y: 0, duration: TimeInterval(0.1 * skyTexture.size().width * 2.0))
    let resetSkySprite = SKAction.moveBy(x: skyTexture.size().width * 2.0, y: 0, duration: 0.0)
    let moveSkySpritesForever = SKAction.repeatForever(SKAction.sequence([moveSkySprite,resetSkySprite]))

    for i:CGFloat in 0 ..< 2.0 + self.frame.size.width / ( skyTexture.size().width * 2.0 ) += 1 {
        let sprite = SKSpriteNode(texture: skyTexture)
        sprite.setScale(2.0)
        sprite.zPosition = -20
        sprite.position = CGPoint(x: i * sprite.size.width, y: sprite.size.height / 2.0 + groundTexture.size().height * 2.0)
        sprite.run(moveSkySpritesForever)
        moving.addChild(sprite)
    }


推荐答案

本质上你想要的仍然是循环通过整数值递增1.所以你可以计算最后一个int值并为每个循环使用一个简单的:

In essence what you want is still a loop through integer values incremented by 1. So you can just calculate the last int value and use a simple for each loop:

for i in 0..<Int(self.frame.size.width / ( skyTexture.size().width * 2.0 )) + 2 {
    //do your stuff here
    sprite.position = CGPoint(x: CGFloat(i) * sprite.size.width, y: sprite.size.height / 2.0 + groundTexture.size().height * 2.0)
}

这篇关于for循环CGFloat出错的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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