iPhone - 最终确定Apple模糊的“VerificationController.m”。 [英] iPhone - finalizing Apple's vague "VerificationController.m"

问题描述

我正在尝试实施新的 VerificationController.m 课程Apple发布修复应用程序内购买欺诈问题。

I am trying to implement the new VerificationController.m class that Apple released to fix the in-app purchase fraud problem.

由于苹果公司发布的所有内容，这是一个更加模糊，不完整和糟糕的解释文档，有很多空白和每个人都无法规避/理解的未知数。

As everything released by Apple, this is one more vague, incomplete and bad explained document with a lot of voids and unknowns that cannot be circumvented/understood by everyone.

我正在努力实现这一点，但在代码的最后我们看到了这四种方法：

I am trying to implement that, but at the end of the code we see these four methods:

- (NSString *)encodeBase64:(const uint8_t *)input length:(NSInteger)length
{
#warning Replace this method.
    return nil;
}

- (NSString *)decodeBase64:(NSString *)input length:(NSInteger *)length
{
#warning Replace this method.
    return nil;
}

#warning Implement this function.
char* base64_encode(const void* buf, size_t size)
{ return NULL; }

#warning Implement this function.
void * base64_decode(const char* s, size_t * data_len)
{ return NULL; }

你可以看到Apple懒得在代码末尾实现C函数。由于我的C / C ++能力很糟糕，我发现我需要在C / C ++中实现这两个函数，并且它们必须返回char和void（???）。其他人已经发布了在SO上执行此操作的例程，但他们要么在Objective-C中，要么不返回chars和void（??）。

You can see that Apple was lazy to implement the C functions at the end of the code. As my C/C++ abilities stink, I see I need to implement these two functions in C/C++ and that they must return char and void (???). Other people have posted routines to do that on SO, but they are either in Objective-C or not returning chars and void (??).

注意：这是我的另一个问题：如果Apple以这种形式使用它，方法如何返回void？

uint8_t *purchase_info_bytes = base64_decode([purchase_info_string cStringUsingEncoding:NSASCIIStringEncoding],                                                 &purchase_info_length);

不应该返回uint8_t吗？

shouldn't it be returning uint8_t?

注意2：我遇到的另一个问题是apple表示base64_encode是必需的，但它没有在它们提供的代码上使用。我认为他们吸烟不好或我的C / C ++知识真的很臭。

所以，回到我的第一个问题。有人可以发布/指出一个方法，可以完成遵循声明的方法base64_encode和base64_decode的要求的工作吗？请不要发布与Apple强加的这些要求不相符的Objective-c方法。

So, returning to my first question. Can someone post/point a method that can do the job that follows the requirements of the declared methods base64_encode and base64_decode? Please refrain from posting objective-c methods that are not compatible with these requirements imposed by Apple.

谢谢。

推荐答案

解决方案 应该非常简单，其中包括填充缺失信息的所有方法。在沙盒中经过测试和功能。

This solution should be pretty straight forward, which includes all the methods to populate the missing information. Tested and functional within the sandbox.

//  single base64 character conversion
static int POS(char c)
{
    if (c>='A' && c<='Z') return c - 'A';
    if (c>='a' && c<='z') return c - 'a' + 26;
    if (c>='0' && c<='9') return c - '0' + 52;
    if (c == '+') return 62;
    if (c == '/') return 63;
    if (c == '=') return -1;

    [NSException raise:@"invalid BASE64 encoding" format:@"Invalid BASE64 encoding"];
    return 0;
}

- (NSString *)encodeBase64:(const uint8_t *)input length:(NSInteger)length
{
    return [NSString stringWithUTF8String:base64_encode(input, (size_t)length)];
}

- (NSString *)decodeBase64:(NSString *)input length:(NSInteger *)length
{
    size_t retLen;
    uint8_t *retStr = base64_decode([input UTF8String], &retLen);
    if (length)
        *length = (NSInteger)retLen;
    NSString *st = [[[NSString alloc] initWithBytes:retStr
                                             length:retLen
                                           encoding:NSUTF8StringEncoding] autorelease];
    free(retStr);    // If base64_decode returns dynamically allocated memory
    return st;
}

char* base64_encode(const void* buf, size_t size)
{
    static const char base64[] =  "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";

    char* str = (char*) malloc((size+3)*4/3 + 1);

    char* p = str;
    unsigned char* q = (unsigned char*) buf;
    size_t i = 0;

    while(i < size) {
        int c = q[i++];
        c *= 256;
        if (i < size) c += q[i];
        i++;

        c *= 256;
        if (i < size) c += q[i];
        i++;

        *p++ = base64[(c & 0x00fc0000) >> 18];
        *p++ = base64[(c & 0x0003f000) >> 12];

        if (i > size + 1)
            *p++ = '=';
        else
            *p++ = base64[(c & 0x00000fc0) >> 6];

        if (i > size)
            *p++ = '=';
        else
            *p++ = base64[c & 0x0000003f];
    }

    *p = 0;

    return str;
}

void* base64_decode(const char* s, size_t* data_len_ptr)
{
    size_t len = strlen(s);

    if (len % 4)
        [NSException raise:@"Invalid input in base64_decode" format:@"%d is an invalid length for an input string for BASE64 decoding", len];

    unsigned char* data = (unsigned char*) malloc(len/4*3);

    int n[4];
    unsigned char* q = (unsigned char*) data;

    for(const char*p=s; *p; )
    {
        n[0] = POS(*p++);
        n[1] = POS(*p++);
        n[2] = POS(*p++);
        n[3] = POS(*p++);

        if (n[0]==-1 || n[1]==-1)
            [NSException raise:@"Invalid input in base64_decode" format:@"Invalid BASE64 encoding"];

        if (n[2]==-1 && n[3]!=-1)
            [NSException raise:@"Invalid input in base64_decode" format:@"Invalid BASE64 encoding"];

        q[0] = (n[0] << 2) + (n[1] >> 4);
        if (n[2] != -1) q[1] = ((n[1] & 15) << 4) + (n[2] >> 2);
        if (n[3] != -1) q[2] = ((n[2] & 3) << 6) + n[3];
        q += 3;
    }

    // make sure that data_len_ptr is not null
    if (!data_len_ptr)
        [NSException raise:@"Invalid input in base64_decode" format:@"Invalid destination for output string length"];

    *data_len_ptr = q-data - (n[2]==-1) - (n[3]==-1);

    return data;
}

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