使用Swift 3解析JSON响应 [英] Parse JSON response with Swift 3
本文介绍了使用Swift 3解析JSON响应的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我的JSON看起来像这样:
I have JSON looking like this:
{"posts":
[
{
"id":"1","title":"title 1"
},
{
"id":"2","title":"title 2"
},
{
"id":"3","title":"title 3"
},
{
"id":"4","title":"title 4"
},
{
"id":"5","title":"title 5"
}
],
"text":"Some text",
"result":1
}
如何用Swift 3解析那个JSON?
How can I parse that JSON with Swift 3?
我有这个:
let url = URL(string: "http://domain.com/file.php")!
let request = URLRequest(url: url)
let task = URLSession.shared.dataTask(with: request) { data, response, error in
guard let data = data else {
print("request failed \(error)")
return
}
do {
if let json = try JSONSerialization.jsonObject(with: data) as? [String: String], let result = json["result"] {
// Parse JSON
}
} catch let parseError {
print("parsing error: \(parseError)")
let responseString = String(data: data, encoding: .utf8)
print("raw response: \(responseString)")
}
}
task.resume()
}
推荐答案
使用它来解析您的数据:
Use this to parse your data:
let url = URL(string: "http://domain.com/file.php")
URLSession.shared.dataTask(with:url!, completionHandler: {(data, response, error) in
guard let data = data, error == nil else { return }
do {
let json = try JSONSerialization.jsonObject(with: data, options: .allowFragments) as! [String:Any]
let posts = json["posts"] as? [[String: Any]] ?? []
print(posts)
} catch let error as NSError {
print(error)
}
}).resume()
使用后卫
检查您是否有数据并且该错误是空的。
Use guard
to check if you have data and that error is empty.
这篇关于使用Swift 3解析JSON响应的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文