NSInteger计算时间4？ [英] NSInteger counts times 4?

问题描述

我不明白为什么这个NSInteger计数器增加到数据库行的真实值的4倍。也许这是愚蠢的，但我真的只是不明白......

I don't understand why this NSInteger counter increments to exactly 4 times the true value of database rows. Maybe this is stupid but I really just don't get it...

到目前为止感谢：）

NSInteger *i;
i = 0;

for ( NSDictionary *teil in gText ) {

    //NSLog(@"%@", [teil valueForKey:@"Inhalt"]);

    [databaseWrapper addEntry:[teil valueForKey:@"Inhalt"] withTyp:[teil valueForKey:@"Typ"] withParagraph:[teil valueForKey:@"Paragraph"]];

    i+=1;
}

NSLog(@"Number of rows created: %d", i);

推荐答案

因为我是一个指针，你正在递增指针值最有可能是4的步长（NSInteger指针的大小）。只需删除指针*引用就可以了。

Because i is a pointer and you are incrementing the pointer value which will most likely be in steps of 4 (size of NSInteger pointer). Just remove the pointer * reference and you should be good.

NSInteger i = 0;

for ( NSDictionary *teil in gText ) {

理论上你可以这样做很难。

In theory you COULD do this the hard way.

NSInteger *i;
*i = 0;
for ( NSDictionary *teil in gText ) {
...
*i = *i + 1;
...

来自：
基础数据类型参考

#if __LP64__ || TARGET_OS_EMBEDDED || TARGET_OS_IPHONE || TARGET_OS_WIN32 || NS_BUILD_32_LIKE_64
typedef long NSInteger;
#else
typedef int NSInteger;
#endif

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