iOS:仅绘制UImage的一部分 [英] iOS: Drawing just portions of a UImage
问题描述
我试图只绘制 UIImage
的自定义部分(即:我想揭示 <$ c的部分$ c> UIImage 用户触摸)我使用图层的
。掩码
属性获得了合理的结果
I am trying to draw just a custom portion of a UIImage
(i.e.: I would like to reveal the portion of the UIImage
user touches) and I am having reasonable results by using mask
property of the layer
.
我的 UIView
上有类似的东西:
UIBezierPath *maskPath = [UIBezierPath bezierPath];
[maskPath setLineWidth:10.0];
[maskPath moveToPoint:CGPointMake(10.0, 10.0)];
[maskPath addLineToPoint:CGPointMake(100.0, 100.0)];
CAShapeLayer *shapeMaskLayer = [CAShapeLayer layer];
shapeMaskLayer.path = maskPath.CGPath;
[self.layer setMask:shapeMaskLayer];
然后,在 drawRect
:
- (void)drawRect:(CGRect)rect
{
[img drawInRect:rect];
}
它有效。我只是看到由 maskPath
定义的图像部分。
It works. I am just seeing the portion of the image defined by maskPath
.
然而,看起来不是那个解决这个问题的最佳方法。所以我的问题是:在iOS SDK中绘制图像的自定义部分(可能是任何形状)的最佳方法是什么?。
However, doesn't look that that's the best way of approaching this issue. So my question is: What would be the best way of drawing just a custom portion (it could be any shape) of an image in iOS SDK?.
推荐答案
您可以尝试的一件事就是剪切而不是创建额外的图层。例如
One thing you could try is simply clipping instead of creating an extra layer. e.g.
- (void)drawRect:(CGRect)rect
{
CGContextRef ctx = UIGraphicsGetCurrentContext();
UIBezierPath *maskPath = [UIBezierPath bezierPath];
[maskPath setLineWidth:10.0];
[maskPath moveToPoint:CGPointMake(10.0, 10.0)];
[maskPath addLineToPoint:CGPointMake(100.0, 100.0)];
CGContextAddPath(ctx, maskPath.CGPath);
CGContextClip(ctx)
[img drawInRect:rect];
}
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