如何在iOS中将整个UITableView渲染为UIImage？ [英] How to render a whole UITableView as an UIImage in iOS?

问题描述

我有一些简单的 UITableView 和一些数据。桌子的高度大于屏幕尺寸。现在我需要抓住这个表的截图（整个表格）。我知道内容后的单元格已经出列，但也许有一种方法可以捕获它。不是吗？

I have simple UITableView with some data. The table's height is greater than the screen size. Now I need to catch screenshot of this table (a whole table). I know that cells after the content are dequeued, but maybe there is a way how to capture this. isn't it?

推荐答案

试试这个：

 func generateImage(tblview:UITableView) ->UIImage{
        UIGraphicsBeginImageContext(tblview.contentSize);
        tblview.scrollToRowAtIndexPath(NSIndexPath(forRow: 0, inSection: 0), atScrollPosition: UITableViewScrollPosition.Top, animated: false)
        tblview.layer.renderInContext(UIGraphicsGetCurrentContext())
        let row = tblview.numberOfRowsInSection(0)
        let numberofRowthatShowinscreen = 4
        var scrollCount = row / numberofRowthatShowinscreen

        for var i=0;i < scrollCount ; i++ {
            tblview.scrollToRowAtIndexPath(NSIndexPath(forRow: (i+1)*numberofRowthatShowinscreen, inSection: 0), atScrollPosition: UITableViewScrollPosition.Top, animated: false)
            tblview.layer.renderInContext(UIGraphicsGetCurrentContext())
        }

        let image:UIImage = UIGraphicsGetImageFromCurrentImageContext()
        UIGraphicsEndImageContext();
        return image;
}

以及此后的通话方式。

 var imageView = UIImageView()
     imageView.image =generateImage(tableView)

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