Swift：触发TableViewCell以在另一个ViewController中的UIWebView中引导链接 [英] Swift: Triggering TableViewCell to lead to a link in a UIWebView in another ViewController

问题描述

当我点击 tableViewCell 时，我想要一个链接（特定于该单元格的 indexPath.row ）在一个带有webView的新viewController中打开。

When i tap a tableViewCell I want a link (that is specific to that cell's indexPath.row) to open up in a new viewController with a webView.

示例：我点击 tableView 中的第3个单元格，并在新的viewController上打开www.apple.com 。

Example: I tap the 3rd cell in the tableView and www.apple.com opens up on a new viewController.

我试图用 didSelectRowAtIndexPath 来做到这一点，但我无法弄清楚如何放置代码一起，当我点击 tableViewCell 时，来自 linksArray （我存储了所有链接）的代码一起工作

I'm trying to do that with didSelectRowAtIndexPath but I can't figure out how to put the code together so that the code from the linksArray (where i have all the links stored) works together when I tap the tableViewCell

我正在从Parse.com查询这些链接。这是我的数组：

I'm querying these links from Parse.com. This is my array:

var linksArray = [NSURL]（）

我创建了一个名为 LinkViewViewController 的新类，其中我只将webView连接为 @IBOutlet弱变量webView：UIWebView！而没有别的。我拿出了 viewDidLoad 方法，以便我可以从 FeedTableViewController控制 LinkViewViewController code>包含单元格的类。

I created a new Class called LinkViewViewController where I have just the webView connected as a @IBOutlet weak var webView: UIWebView! and nothing else. I took out the viewDidLoad method so that I can control the LinkViewViewController from the FeedTableViewController class that has the cells.

这是我下面的代码

 override func tableView(tableView: UITableView,  didSelectRowAtIndexPath indexPath: NSIndexPath) {

    let myWebView = tableView.dequeueReusableCellWithIdentifier("cell",    forIndexPath: indexPath) as! LinkViewViewController

    var url = NSURL(string:"\(links[indexPath.row])")

    var request = NSURLRequest(URL: url!)

    myWebView.webView.loadRequest(links[indexPath.row] as! NSURLRequest)

}

更新

我也试图这样做，这可能更符合逻辑。我正在访问ProductInfo类中存储在Parse中的链接。 productName 数组表示单元格的组织顺序，以便在点击产品名称时可以访问链接。

I am also trying to do it this way, which maybe more logical. I am accessing the links that are stored in Parse in the ProductInfo class. The productName array represents in what order the cells are organized in so that the the links can be accessed when tapping on the product name.

   override func tableView(tableView: UITableView,  didSelectRowAtIndexPath indexPath: NSIndexPath) {

    let myWebView = tableView.dequeueReusableCellWithIdentifier("cell",    forIndexPath: indexPath) as! LinkViewViewController
  //Assuming that myWebView is the right method/way to go about it. 

    var link = PFObject(className: "ProductInfo")

    link["pLink"] = productName[indexPath.row]


       /* Code missing: I'm accessing where the link is (the
        indexPath.row) associated with the productName. 
        I don't know how to go about this now... How do i access the 
        webView in the other viewController where the corresponding 
        link appears?

        */
}

我也尝试过创建从单元格到webView的segue但是也没有... ...

I've also tried creating a segue from the cell to the webView but that didn't work either...

如何设置 didSelectRowAtIndexPath 以便触发链接出现在新视图中？

How can I set up the didSelectRowAtIndexPath so that a link is triggered to appear in a new view?

想法： info.plist 中的NSTransportSecurity 一个问题？

Thought: NSTransportSecurity in the info.plist also an issue?

任何帮助意味着很多。

谢谢。

推荐答案

您不应该使用 dequeueReusableCellWithIdentifier 来创建下一个视图控制器。您应该使用故事板的 instantiateViewControllerWithIdentifier 来创建实例：在故事板中为viewController设置Storyboard ID

You should not be using dequeueReusableCellWithIdentifier to create your next view controller. You should use the storyboard's instantiateViewControllerWithIdentifier to create the instance: Set the "Storyboard ID" for the viewController in your storyboard

如果将其设置为WebViewController，则可以使用以下命令创建实例：

If you set it to, for example, "WebViewController" you can then create the instance with:

let myWebView = self.storyboard!.instantiateViewControllerWithIdentifier("WebViewController") as! LinkViewViewController

我的建议是给 LinkViewViewController 它自己的URL属性，

My recommendation would be to give the LinkViewViewController its own URL property,

var url : NSURL?

并在创建实例后传递URL：

and to pass the URL after creating the instance:

myWebView.url = url

然后出现新的VC：

self.presentViewController(myWebView, animated: true, completion: nil)

在LinkViewViewController的 viewDidLoad 中，将URL加载到webView中：

In the viewDidLoad of LinkViewViewController, load the URL into the webView:

let URLRequest = NSURLRequest(self.url)
self.webView.loadRequest(URLRequest)

（未经测试输入;请原谅选项中的任何拼写错误/错误等）。

(Typed without testing; please forgive any typos/errors with optionals etc).

作为最后一点，此方法使用 didSelectRow 方法创建视图控制器实例并传递URL。另一种选择是通过从原型单元格拖动到视图控制器来使用segue。然后，您需要在 prepareForSegue 方法中实现类似的代码来设置网址。

As a final note, this method uses the didSelectRow method to create the view controller instance and pass the URL. Another option would be to use a segue by ctrl-dragging from the prototype cell to the view controller. You then need to implement similar code in prepareForSegue method to set the url.

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