将单个数组分成两个数组的代码如何？ [英] How is the code for separation of single array into two arrays?

问题描述

当我从我所需的URL使用JSON解析时，我的响应低于nsarray，但在这里我不想得到2,1,4,4,6,5,8,7,10,9， 12和11在单个数组中我必须得到两个数组的总响应我的意思是一个数组将包括2,4,6,8,10和其他数组必须是3,5,7,9和11。

I am getting below response into the nsarray when I used the JSON parsing from my required URL but here I don't like to get 2,1,4,4,6,5,8,7,10,9,12 and 11 in single array I have to get total response into two arrays I mean one array set will consists 2,4,6,8,10 and other array set must be 3,5,7,9 and 11.

那么在iPhone中将单个数组响应分离为两个数组的代码如何？

So how is the code for separation of single array response into two arrays in iPhone?

"(\n    2,\n    1\n)",
"(\n    4,\n    3\n)",
"(\n    6,\n    5\n)",
"(\n    8,\n    7\n)",
"(\n    10,\n    9\n)",
"(\n    12,\n    11\n)"

推荐答案

如果将每个数字组合成一个大型数组，您可以切实地测试每个数字数字是偶数或奇数，在for-in循环中使用简单的if-else。也许是这样的：

If you combine every number into one large array, you could feasibly test if each number is even or odd with a simple if-else in a for-in loop. Maybe like this:

-(NSArray*)parseJSONIntoArrays:(NSArray*)array {
    NSMutableArray *evenNumbers = [[NSMutableArray alloc]init];
    NSMutableArray *oddNumbers = [[NSMutableArray alloc]init];

    for (NSNumber *number in array) {
        if (([number intValue] %2) == 0) {
            //even
            [evenNumbers addObject:number];
        }
        else {
            //odd
            [oddNumbers addObject:number];
        }
    }
    return [[NSArray alloc]initWithObjects:evenNumbers, oddNumbers, nil];
}

这篇关于将单个数组分成两个数组的代码如何？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！