如何将NSString转换为NSArray [英] how to convert NSString to NSArray

问题描述

我有一个字符串

NSString* str = @"[90, 5, 6]";

我需要将其转换为数组

NSArray * numbers = [90, 5 , 6];

我做了很长的路：

+ (NSArray*) stringToArray:(NSString*)str
{
    NSString *sep = @"[,";
    NSCharacterSet *set = [NSCharacterSet characterSetWithCharactersInString:sep];
    NSArray *temp=[str componentsSeparatedByCharactersInSet:set];

    NSMutableArray* numbers = [[NSMutableArray alloc] init];
    for (NSString* s in temp) {
        NSNumber *n = [NSNumber numberWithInteger:[s integerValue]];
        [numbers addObject:n];
    }

    return numbers;
}

是否有任何简洁快捷的方式进行此类转换？

Is there any neat and quick way to do such conversion?

谢谢

推荐答案

首先从字符串中删除不需要的字符，喜欢白色空格和大括号：

First remove the unwanted characters from the string, like white spaces and braces:

NSString* str = @"[90, 5, 6]";
NSCharacterSet* characterSet = [[NSCharacterSet
                                 characterSetWithCharactersInString:@"0123456789,"] invertedSet];
NSString* newString = [[str componentsSeparatedByCharactersInSet:characterSet]
                       componentsJoinedByString:@""];

您将拥有如下字符串： 90,5,6 。然后简单地使用逗号分割并转换为 NSNumber ：

You will have a string like this: 90,5,6. Then simply split using the comma and convert to NSNumber:

NSArray* arrayOfStrings = [newString componentsSeparatedByString:@","];
NSMutableArray* arrayOfNumbers = [NSMutableArray arrayWithCapacity:arrayOfStrings.count];
for (NSString* string in arrayOfStrings) {
    [arrayOfNumbers addObject:[NSDecimalNumber decimalNumberWithString:string]];
}

使用 NSString 来自此回复的类别可以简化为：

Using the NSString category from this response it can be simplified to:

NSArray* arrayOfStrings = [newString componentsSeparatedByString:@","];
NSArray* arrayOfNumbers = [arrayOfStrings valueForKey: @"decimalNumberValue"];

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