objective-C，对包含数字的字符串数组进行排序 [英] objective-C, sort an array of strings containing numbers

问题描述

假设我有一个像这样的数组

Lets suppose I have an array like this

NSArray* arr = @[@"1",@"4",@"2",@"8",@"11",@"10",@"14",@"9"]; //note: strings containing numbers

我希望对它们进行排序：[1,2， 4,8,9,10,11,14]

and I want to sort them like this: [1,2,4,8,9,10,11,14]

但如果我使用

[arr sortedArrayUsingSelector:@selector(localizedCaseInsensitiveCompare:)];

我得到[1,10,11,14,2,4,8,9] ..如果我使用：

I get [1,10,11,14,2,4,8,9]... and if I use:

   NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"length" ascending:YES];
   NSArray *sortDescriptors = @[sortDescriptor];
   [arr sortedArrayUsingDescriptors:sortDescriptors];

我得到这样的东西：[1,4,2,8,9,11,10， 14]

I get something like this: [1,4,2,8,9,11,10,14]

如何组合两个谓词？或者是解决这个问题的其他更简单的方法吗？注意：这个数组的输出仅用于调试目的，我不在乎结果是否将数组转换为整数，只要我可以在控制台中使用NSLog打印谢谢

How can I combine both predicates? or is any other easier way to solve this? note: The output of this array is merely for debug purposes, I dont care if the result turns the array into integers as long as I can print in console with NSLog thanks

推荐答案

尝试使用块

[arr sortedArrayUsingComparator:^NSComparisonResult(id obj1, id obj2) {

    if ([obj1 intValue] == [obj2 intValue])
        return NSOrderedSame;

    else if ([obj1 intValue] < [obj2 intValue])
        return NSOrderedAscending;

    else
        return NSOrderedDescending;

}];

这篇关于objective-C，对包含数字的字符串数组进行排序的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！