单击UIAlertview上的按钮后，iOS应用程序立即崩溃 [英] The iOS app crashed right after clicking the button on a UIAlertview

问题描述

用户点击UIAlertview上的按钮后，我尝试使用手机应用程序拨号。手机应用程序确实已打开，但原始应用程序在单击UIAlertview上的按钮后立即崩溃。有人知道原因吗？我确实试图确保我发布了应该发布的所有内容。谢谢！以下是代码：

I tried to dial a number with the phone app after the user click on a button on a UIAlertview. The phone app did open, but the original app crashed right after clicking the button on the UIAlertview. Does anyone one know the reason? I did try to make sure I released everything that should be released. Thanks! Below is the code:

-(IBAction)dialButtonPressed:(UIButton *)numberButton
    {
    if ([company isEqualToString:@"Not Found"]==true){
            message = [[UIAlertView alloc] initWithTitle:@"Sorry"
                                                              message:@"No replace number found. Would you like to dial anyway?"
                                                             delegate:self
                                                    cancelButtonTitle:@"No"
                                                    otherButtonTitles:@"Yes", nil];
            message.tag = 0;
            if(phoneLinkString)
            {
                [phoneLinkString release];
                phoneLinkString = nil;
            }
            [message show];
            [message autorelease];
            phoneLinkString = [[NSString stringWithFormat:@"tel:%@",replace]retain];


        }
    }

- (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
    {
        NSString *title = [alertView buttonTitleAtIndex:buttonIndex];
        [self release];

        message = nil;


        if(message.tag == 0 && buttonIndex == 1){
            NSURL *phoneLinkURL = [NSURL URLWithString:phoneLinkString];
            [[UIApplication sharedApplication] openURL:phoneLinkURL];
        }

- (void)dealloc {
    [phoneNumberString release];
    [phoneNumberLabel release];
    [self release];
    [message release];
    [super dealloc];
}

最新代码

    -(IBAction)dialButtonPressed:(UIButton *)numberButton
            {
            if ([company isEqualToString:@"Not Found"]==true){
                    message = [[UIAlertView alloc] initWithTitle:@"Sorry"
                                                                      message:@"No replace number found. Would you like to dial anyway?"
                                                                     delegate:self
                                                            cancelButtonTitle:@"No"
                                                            otherButtonTitles:@"Yes", nil];
                    message.tag = 1;
                    if(phoneLinkString)
                    {
                        [phoneLinkString release];
                        phoneLinkString = nil;
                    }
                    [message show];
                    [message autorelease];
                    phoneLinkString = [[NSString stringWithFormat:@"tel:%@",replace]retain];


                }
        }
- (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
        {

            if(message.tag == 1 && buttonIndex == 1){

                NSURL *phoneLinkURL = [NSURL URLWithString:phoneLinkString];
                [[UIApplication sharedApplication] openURL:phoneLinkURL];
                message = nil;
            }
        }
- (void)dealloc {
            [phoneNumberString release];
            [phoneNumberLabel release];
            [super dealloc];
        }

但点击UIAlertview上的按钮后仍然崩溃。错误是0x3beb85b0：ldr r3，[r4，＃8] EXC_BAD_ACCESS（代码= 1，地址= 0x7269634f）任何帮助将不胜感激。谢谢！

but it still crashed after clicking the button on the UIAlertview. The error is 0x3beb85b0: ldr r3, [r4, #8] EXC_BAD_ACCESS (code=1, address=0x7269634f) Any help would be appreciated. Thanks!

推荐答案

由于此代码，崩溃正在发生。 [自我发布]; 。
当您致电 self release 显示警报的视图将被释放并取消分配，而不是alertView。这就是崩溃的原因。

The crash is happening due to this code. [self release];. When you call self release the view in which the alert is displayed will released and deallocated, not the alertView. That's the cause of crash.

您已经使用<$ c在 dialButtonPressed：方法中释放alertViews内存$ c> [message autorelease];

You are already releasing the alertViews memory in the dialButtonPressed: method using [message autorelease];

因此无需再次在 clickedButtonAtIndex 。所以更改方法如：

So no need to release the alertView again in clickedButtonAtIndex. So change the method like:

- (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
{
    NSString *title = [alertView buttonTitleAtIndex:buttonIndex];
    if(alertView.tag == 0 && buttonIndex == 1)
    {
        NSURL *phoneLinkURL = [NSURL URLWithString:phoneLinkString];
        [[UIApplication sharedApplication] openURL:phoneLinkURL];
    }
    message = nil;
}

这篇关于单击UIAlertview上的按钮后，iOS应用程序立即崩溃的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！