如何在NSString中捕获特殊指示的**字符**并加粗它们之间的内容？ [英] How to catch special indicated **characters** in an NSString and bold what's in between?

问题描述

我无法在指定的一对**字符之间加粗任何字符。例如，在这个NSString中：

 狐狸在拐角处跑了**。 
  

应为：狐狸跑到左右角落 p>

这是我的代码：

  NSString * questionString = queryString; 
 NSMutableAttributedString * mutableAttributedString = [[NSMutableAttributedString alloc] initWithString：questionString]; 
 
 NSRange range = [questionString rangeOfString：@\\ *（[^ **] +）\\ *选项：NSRegularExpressionSearch | NSCaseInsensitiveSearch]; 
 if（range.location！= NSNotFound）{
 [mutableAttributedString setAttributes：@ {NSFontAttributeName：[UIFont fontWithName：AGHeavyFontName size：size]} range：range]; 
} 
 
 [[mutableAttributedString mutableString] replaceOccurrencesOfString：@*withString：@options：NSCaseInsensitiveSearch range：NSMakeRange（0，queryString.length）]; 
 
 return mutableAttributedString; 
  

我遇到问题 - 这段代码仍会捕获一对*的字符，所以在这种情况下，

 狐狸已经跑到了拐角处* 
  

仍然会显示为狐狸已经跑到左右角落，当它不应该时。

任何想法？

解决方案

也许这可以帮到你：

http://regex101.com/r/eF6pJ8

\\ * {2}（[^ *] *）\\ * {2}

I'm having trouble bolding any characters between an indicated pair of "**" characters. For example, in this NSString:

  "The Fox has ran **around** the corner."

should read: "The fox has ran around the corner"

here is my code :

NSString *questionString = queryString;
NSMutableAttributedString *mutableAttributedString = [[NSMutableAttributedString alloc] initWithString:questionString];

NSRange range = [questionString rangeOfString:@"\\*([^**]+)\\*" options:NSRegularExpressionSearch|NSCaseInsensitiveSearch];
if (range.location != NSNotFound) {
    [mutableAttributedString setAttributes:@{NSFontAttributeName:[UIFont fontWithName:AGHeavyFontName size:size]} range:range];
}

[[mutableAttributedString mutableString] replaceOccurrencesOfString:@"*" withString:@"" options:NSCaseInsensitiveSearch range:NSMakeRange(0, queryString.length)];

return mutableAttributedString;

I'm having issues- this code will still catch characters with one pair of "*"'s, so in this case,

   "The fox has ran *around the corner*

will still read as "The fox has ran around the corner", when it shouldnt.

Any ideas?

解决方案

Perhaps this may help you:

http://regex101.com/r/eF6pJ8

\\*{2}([^*]*)\\*{2}

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