如何在故事板上制作UIImageView可点击(快速) [英] How do you make an UIImageView on the storyboard clickable (swift)

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本文介绍了如何在故事板上制作UIImageView可点击(快速)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我是swift的新手(以及一般的Xcode开发),我想知道如何使故事板上的ImageView可点击。我正在尝试做的是当它点击时,它显示另一个视图控制器。

I am new to swift (and Xcode development in general) and I was wondering how to make an ImageView on the storyboard clickable. What I'm trying to do is make it so when its clicked, it shows another view controller.

推荐答案

您可以为此添加tapGesture。下面是代码:

You can add tapGesture for that. Here is the code:

class ViewController: UIViewController {

@IBOutlet weak var imageView: UIImageView!
override func viewDidLoad() {
    super.viewDidLoad()
    // create tap gesture recognizer
    let tapGesture = UITapGestureRecognizer(target: self, action: "imageTapped:")

    // add it to the image view;
    imageView.addGestureRecognizer(tapGesture)
    // make sure imageView can be interacted with by user
    imageView.userInteractionEnabled = true
}

func imageTapped(gesture: UIGestureRecognizer) {
    // if the tapped view is a UIImageView then set it to imageview
    if let imageView = gesture.view as? UIImageView {
        println("Image Tapped")
        //Here you can initiate your new ViewController

        }
    }
}

Swift 3.0

class ViewController: UIViewController {

    @IBOutlet weak var imageView: UIImageView!
    override func viewDidLoad() {
        super.viewDidLoad()
        // create tap gesture recognizer
        let tapGesture = UITapGestureRecognizer(target: self, action: #selector(ViewController.imageTapped(gesture:)))

        // add it to the image view;
        imageView.addGestureRecognizer(tapGesture)
        // make sure imageView can be interacted with by user
        imageView.isUserInteractionEnabled = true
    }

    func imageTapped(gesture: UIGestureRecognizer) {
        // if the tapped view is a UIImageView then set it to imageview
        if (gesture.view as? UIImageView) != nil {
            print("Image Tapped")
            //Here you can initiate your new ViewController

        }
    }
}

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