从AVPlayer对象访问URL？ [英] Accessing URL from AVPlayer object?

问题描述

有没有办法从使用URL初始化的AVPlayer对象访问URL，如：

Is there a way to access the URL from an AVPlayer object that has been initialized with a URL, as in:

NSURL *url = [NSURL URLWithString: @"http://www.example.org/audio"];
self.player = [AVPlayer playerWithURL: url];

推荐答案

一个 AVPlayer 播放 AVPlayerItem 。 AVPlayerItem 由类 AVAsset 的对象支持。当您使用 AVPlayer 的 playerWithURL：方法时，它会自动创建 AVPlayerItem 由资产支持，该资产是 AVAsset 的子类，名为 AVURLAsset 。 AVURLAsset 有一个 URL 属性。

An AVPlayer plays an AVPlayerItem. AVPlayerItems are backed by objects of the class AVAsset. When you use the playerWithURL: method of AVPlayer it automatically creates the AVPlayerItem backed by an asset that is a subclass of AVAsset named AVURLAsset. AVURLAsset has a URL property.

所以，是的，在您提供的情况下，您可以非常轻松地获得当前播放项目的 NSURL 。以下是如何执行此操作的示例函数：

So, yes, in the case you provided you can get the NSURL of the currently playing item fairly easily. Here's an example function of how to do this:

-(NSURL *)urlOfCurrentlyPlayingInPlayer:(AVPlayer *)player{
    // get current asset
    AVAsset *currentPlayerAsset = player.currentItem.asset;
    // make sure the current asset is an AVURLAsset
    if (![currentPlayerAsset isKindOfClass:AVURLAsset.class]) return nil;
    // return the NSURL
    return [(AVURLAsset *)currentPlayerAsset URL];
}

不是一个快速的专家，但它似乎可以更迅速地完成。

Not a swift expert, but it seems it can be done in swift more briefly.

func urlOfCurrentlyPlayingInPlayer(player : AVPlayer) -> URL? {
    return ((player.currentItem?.asset) as? AVURLAsset)?.url
}

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