如何在UITableView中获取所有单元格 [英] How to get all cells in a UITableView

问题描述

假设我有一个有多行的UITableView。我希望在某个时间点将所有UITableViewCells作为NSArray。我试过了

Let's say I have a UITableView which has multiple rows. I want to get all the UITableViewCells as an NSArray at a certain point of time. I have tried

[tableView visibleCells] 

但这种方法存在问题：我不能拥有当前屏幕中当前不存在的所有单元格。所以我转向另一种方法：

but there is a problem with this approach: I can not have all those cells which are not currently in the current screen. So I turned to another approach:

-(NSArray *)cellsForTableView:(UITableView *)tableView
{
    NSInteger sections = tableView.numberOfSections;
    NSMutableArray *cells = [[NSMutableArray alloc]  init];
    for (int section = 0; section < sections; section++) {
        NSInteger rows =  [tableView numberOfRowsInSection:section];
        for (int row = 0; row < rows; row++) {
            NSIndexPath *indexPath = [NSIndexPath indexPathForRow:row inSection:section];
            UITableViewCell *cell = [self.tableView cellForRowAtIndexPath:indexPath];   // **here, for those cells not in current screen, cell is nil**
            [cells addObject:cell];
        }
    }
    return cells;
}

但似乎这种方法仍然无法获得那些未显示的单元格屏幕。任何人都可以帮我吗？

but seems that this approach still can not get those cells which are not displayed in the screen. Can anyone help me on this?

推荐答案

我认为这不可能，因为tableView不存储所有单元格。它使用缓存机制，该机制仅存储一些不可见的单元以供重用。

I don't think thats possible, simply because the tableView doesn't store all cells. It uses a caching mechanism which only stores some cells, that are not visible, for reuse.

为什么需要所有细胞？也许你可以实现，你正在尝试做什么，否则。

Why do you need all cells? Maybe you can achieve, what you're trying to do, otherwise.

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