如何使用Instruments（Leaks） - Xcode找到C或C ++代码泄漏？ [英] How to find C or C++ code leaks using Instruments (Leaks) - Xcode?

问题描述

int* foo = new int[10];
foo = NULL;
sleep(60);

仪器在上面的代码中没有发现任何泄漏，我如何使用仪器工具查找C或C ++代码泄漏。我有堆栈溢出大多数解释是基于客观C代码...

Instrument is not finding any leak in above code, how do I use Instrument tool to find C or C++ code leaks. I have stack overflowed most of the explanation is based on objective C codes...

推荐答案

问题是编译器会优化出来在以下代码片段中调用 new ：

The issue is that compiler will optimize out the call to new in the following code fragment:

int* foo = new int[10];
foo = NULL;
sleep(60);

因为它足够聪明，知道它没有被使用。如果您添加代码以使用 foo ，那么编译器将不会执行此操作，您应该会看到预期的泄漏：

as it's smart enough to know that it's not being used. If you add code to use foo then compiler won't do this and you should see the leak you are expecting:

int* foo = new int[10];

foo[3] = 23;
foo[8] = 45;

printf("%d %d\n", foo[3], foo[8]);

foo = NULL;
sleep(60);

这篇关于如何使用Instruments（Leaks） - Xcode找到C或C ++代码泄漏？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！